model 3 based on positive and negative exponent Practice Questions Answers Test with Solutions & More Shortcuts

Question : 31 [SSC CGL Prelim 2002]

If $(125)^{2/3}× (625)^{ - 1/4} = 5^x$ the value of x is

a) 2

b) 1

c) 0

d) 3

Answer:(b)

$(125)^{2/3}× (625)^{ - 1/4} = 5^x$

$5^{3×2/3}×5^{4×-1/4}=5^x$

$5^2×5^{-1}=5^x$

$5^1=5^x⇒ x=1$

Question : 32

If $3^10 × 27^2 = 9^2 × 3^n$ then the value of n is :

a) 12

b) 30

c) 15

d) 10

Answer:(a)

$3^10 × 27^2 = 9^2 × 3^n$

$3^10 × (3^3)^2 = (3^2)^2 × 3^n$

$3^10 × 3^6 = 3^4 × 3^n$

$3^{10+6} = 3^4 × 3^n$

$3^16 = 3^{4 + n}$

4 + n = 16

n = 16 - 4 = 12

Question : 33 [SSC CGL Tier-I 2016]

If $x = 3^{1/3}- 3^{-1/3}$, then the value of ($3x^3$ + 9x) is :

a) 9

b) 16

c) 27

d) 8

Answer:(d)

$x = (3)^{1/3} - (3)^{-1/3}$

On cubing both sides,

$x^3 = ((3)^{1/3} - (3)^{-1/3})^3$

= $((3)^{1/3})^3-((3)^{-1/3})^3-3×3^{1/3}×3^{-1/3}(3^{1/3}-3^{-1/3})$

=$3-3^{-1}-3×x=3-1/3-3x$

$x^3 + 3x = 3- 1/3={9- 1}/3$

$x^3 + 3x = 8/3$

$3x^3 + 9x = 8/3 ×3 =8$

Question : 34 [SSC CGL Tier-I 2015]

The mean of $1^3 , 2^3 , 3^3 , 4^3 , 5^3 , 6^3 , 7^3$ is

a) 112

b) 28

c) 56

d) 20

Answer:(a)

Sum of the cubes of first n natural numbers = $({n(n + 1)}/2)^2$

Their average = ${n(n+1)^2}/4$

Required average when n = 7,

= ${7(7+ 1)^2}/4 = {7 × 8×8}/4$ = 112

Question : 35 [SSC CGL Tier-I 2016]

The value of $(x^{1/3}+x^{-1/3})(x^{2/3}+x^{-2/3})$ is

a) $x + x^{ - 1/3}$

b) $x + x^{ - 1}$

c) $x^{1/3} + x^{ - 1}$

d) $x^{ - 1} + x^{2/3}$

Answer:(b)

$(a+b)(a^2-ab+b^2)=a^3+b^3$

$(x^{1/3}+x^{-1/3})(x^{2/3}-1+x^{-2/3})$

=$(x^{1/3}+x^{-1/3})((x^{1/3})^2-x^{1/3}.x^{-1/3}+(x^{-1/3})^2)$

=$(x^{1/3})^3+(x^{-1/3})^3$

$x+x^{-1}=x+1/x$

IMPORTANT quantitative aptitude EXERCISES

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