model 3 based on positive and negative exponent Practice Questions Answers Test with Solutions & More Shortcuts

Question : 6 [SSC CGL Tier-II 2015]

The unit digit in the product $(2467)^153 × (341)^72$ is

a) 3

b) 1

c) 9

d) 7

Answer:(d)

$7^1 = 7, 7^2 = 49, 7^3$ = 343,

$7^4 = 2401, 7^5$ = 16807

i.e. after index 4, the unit's digit is repeated.

On dividing 153 by 4, remainder = 1

Unit's digit in the expansion of $(2467)^153=7^1$=7 and unit's digit in the expansion of $(341)^72$ = 1

Required unit's digit = 7 × 1 = 7

Question : 7 [SSC CAPFs SI 2014]

A tap is dripping at a constant rate into a container. The level (L cm) of the water in the container is given by the equation L = 2 - $2^t$, where t is time taken in hours. Then the level of water in the container at the start is

a) 1 cm

b) 4 cm

c) 2 cm

d) 0 cm

Answer:(a)

L = 2 - $2^t$

At the start, t = 0

L = 2 - 2° = 2 - 1 = 1 cm

Question : 8

If $√{3n}$ = 2187 then the value of n is :

a) 14

b) 16

c) 15

d) 13

Answer:(a)

$√{3^n}$ = 2187

$3^{n/2} = (3)^7$

$n/2$ = 7

n = 2 × 7 = 14

Question : 9 [SSC CGL Prelim 1999]

If $3^{x+8} = 27^{2x+1}$, the value of x is :

a) 3

b) 1

c) - 2

d) 7

Answer:(b)

$3^{x+8} = 27^{2x+1}$

$3^{x+8} = (3)^{3(2x+1)}$

x + 8 = 6x + 3

5x = 5 ∴ x=1

Question : 10 [SSC CPO 2016]

What will be the remainder when $252^126+244^152$ is divided by 10 ?

a) 6

b) 8

c) 0

d) 4

Answer:(c)

Unit's digit in the expansion of $(252)^126$

= $2^2$ = 4 (Remainder on dividing 126 by 4 = 2)

Unit's digit in the expansion of $(244)^152$ = 6

Unit's digit in the expansion of $252^126 + 244^152$ = 0

Required remainder = 0

IMPORTANT quantitative aptitude EXERCISES

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