Mensuration Model Questions Set 1 Practice Questions Answers Test with Solutions & More Shortcuts
Mensuration PRACTICE TEST [2 - EXERCISES]
Mensuration Model Questions Set 1
Mensuration Model Questions Set 2
Question : 11
Let AB and AC be two rays intersecting at A. If D, E be the points lying on AB, AC respectively and P be the point such that P divides the line DE such that PD : PE = AD : AE. Then, what is the locus of the point P?
a) The perpendicular bisector of angle A
b) The angle bisector of angle A
c) The angle trisector of angle A
d) None of the above
Answer »Answer: (b)
Since, ${PD}/{PE} = {AD}/{AE} = {AP}/{AP}$
ΔDAP and ΔAPE are similar. So, ∠1 = ∠2
AP is bisector of ∠A.
Hence, the locus of P is the bisector of angle A.
Question : 12
A horse is tethered to one corner of a rectangular grassy field 40 m by 24 m with a rope 14 m long. Over how much area of the field can it graze ?
a) 150 $m^2$
b) 154 $cm^2$
c) 308 $m^2$
d) None of these
Answer »Answer: (b)
Area of the shaded portion
= $1/4 × π (14)^2$
= 154 $m^2$
Question : 13
Consider a circle C of radius 6 cm with centre at O. What is the difference in the area of the circle C and the area of the sector of C subtending an angle of 80º at O?
a) 28π $cm^2$
b) 26π $cm^2$
c) 16π $cm^2$
d) 30π$cm^2$
Answer »Answer: (a)
Radius of circle, r = 6 cm
∴ Area of circle = $πr^2 = π × 6^2 = 36π cm^2$
and Area of sector subtending an angle of 80° at O
= ${π r^2 θ}/{360°} = {π × 6^2 × 80°}/{360°} = 8 π cm^2$
∴ Required difference = 36π – 8π = 28π $cm^2$
Question : 14
The medians of ΔABC intersect at G. Which one of the following is correct?
a) Three times the area of ΔAGB is equal to the area of ΔABC
b) Five times the area of ΔAGB is equal to four times the area of ΔABC
c) Four times the area of ΔAGB is equal to three times the area of ΔABC
d) None of the above
Answer »Answer: (a)
Suppose ΔABC is an equilateral triangle.
A median divides an equilateral triangle into the three equal area of triangles.
ΔAGB = ar ${(ΔABC)}/3$ = ar BGC = ar ΔAGC
∴ ar ΔAGB = $1/3$ ΔABC.
Question : 15
In the figure given below, PQ is parallel to RS and PR is parallel to QS. If ∠LPR = 35° and ∠ UST = 70°, then what is ∠MPQ equal to ?
a) 75°
b) 55°
c) 70°
d) 80°
Answer »Answer: (a)
PQ || RS
PR|| QS
∴ PQRS is a || gm
∠LPR = 35° and ∠UST = 70°
∠UST = ∠RSQ (Vertically opposite)
∠RSQ = ∠RPQ (opposite angle of 11 gm)
∠LPR + ∠RPQ + ∠MPQ = 180°
35° + 70° + ∠MPQ = 180°
∠MPQ = 180 – 105
∠MPQ = 75°
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