model 2 find lcm of numbers Practice Questions Answers Test with Solutions & More Shortcuts

Question : 51

The least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is :

a) 56

b) 50

c) 48

d) 46

Answer: (b)

Using Rule 4,

i.e. When a number is divided by x, y or z leaving same remainder ‘R’ in each case then that number must be K + R where k is LCM of x, y and z.

L.C.M. of 4, 6, 8, 12 and 16 = 48

∴ Required number = 48 + 2 = 50

IMPORTANT quantitative aptitude EXERCISES

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