model 3 twice, thrice, one third etc. of numbers Practice Questions Answers Test with Solutions & More Shortcuts

Question : 6

Of the three numbers, the first is 3 times the second and the third is 5 times the first. If the average of the three numbers is 57, the difference between the largest and the smallest number is

a) 126

b) 135

c) 9

d) 18

Answer: (a)

Let second number be x

∴ The first number = 3x

and the third number = 15x

Now, x + 3x + 15x = 3 × 57

⇒ 19x = 3 × 57

⇒ x= ${3×57}/19$= 9

∴ Required difference

= 15x – x = 14x

= 14 × 9 = 126

Aliter : Using Rule 15,

From three numbers, first number is 'a’ times of 2nd number, 2nd number is 'b’ times of 3rd number and the average of all three numbers is x, then,

First number = $\text"3ab"/ \text"1+b+ab"$ x ; Second number = $\text"3b"/ \text"1+b+ab"$ x ; Third number = $\text"3b"/ \text"1+b+ab"$ x

a = 3, b = 5, x = 57

First number = $\text"3ab"/ \text"1+b+ab"$x

= ${3×3×5}/{1+3+15}$× 57

= $45/19$ × 57 = 135

Second number = $\text"3ab"/ \text"1+b+ab"$x

= ${3×5}/{19}$× 57

= $15/19$ × 57 = 45

Third number = $3/ \text"1+b+ab"$x

= $3/19$×57 = 9

Required result = 135 – 9 = 126

Question : 7 [SSC CGL Tier-II 2015]

If the arithmetic mean of 3a and 4b is greater than 50, and a is twice b, then the smallest possible integer value of a is

a) 21

b) 19

c) 20

d) 18

Answer: (a)

$\text"3a+4b"/2$ > 50

⇒ 3a + 4b > 100

⇒ 3a + ${4a}/2$ > 100 [Since a = 2b]

⇒ 3a + 2a > 100

⇒ 5a > 100

⇒ a > 20

∴ Minimum value of a = 21

Question : 8 [SSC CPO 2011]

Of the three numbers, the first number is twice of the second and the second is thrice of the third number. If the average of these 3 numbers is 20, then the sum of the largest and smallest numbers is

a) 54

b) 60

c) 24

d) 42

Answer: (d)

Let the third number be x.

∴ Second number = 3x

and first number = 6x

∴ 6x + 3x + x = 3 × 20

⇒ 10x = 60 ⇒ x = 6

∴ Required sum = 6x + x = 7x = 7 × 6 = 42

Aliter : Using Rule 15,

From three numbers, first number is 'a’ times of 2nd number, 2nd number is 'b’ times of 3rd number and the average of all three numbers is x, then,

First number = $\text"3ab"/ \text"1+b+ab"$ x ; Second number = $\text"3b"/ \text"1+b+ab"$ x ; Third number = $\text"3b"/ \text"1+b+ab"$ x

Here, a = 2, b = 3, x = 20

Largest Number= $\text"3ab"/ \text"1+b+ab"$ x

= ${3×2×3}/{1+3+2×3}$×20

=$18/10$×20 = 36

Smallest Number = $3/\text"1+b+ab"$ ×x

= $3/{1+3+2×3}$×20

= $3/10$×20 = 6

Sum = 36 + 6 = 42

Question : 9 [SSC CGL Prelim 2005]

The average of first three numbers is thrice the fourth number. If the average of all the four numbers is 5, then find the fourth number.

a) 2

b) 4

c) 4.5

d) 5

Answer: (a)

Let the numbers be a, b, c,

${\text"a + b + c"}/3$ = 3d

⇒ a + b + c = 9d

Again, ${\text"a + b + c + d"}/4$ = 5

⇒ a + b + c + d = 20

⇒ 9d + d = 20

⇒ 10d = 20 ⇒ d = 2

Question : 10 [SSC CGL Tier-1 2011]

Out of 4 numbers, whose average is 60, the first one is one fourth of the sum of the last three. The first number is

a) 48

b) 60

c) 15

d) 45

Answer: (a)

Let the first number be x,

then, x = ${240 - x}/4$

⇒ 4x = 240 – x

⇒ 5x = 240

⇒ x = $240/5$ = 48

IMPORTANT quantitative aptitude EXERCISES

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