model 9 average on cricket/exam Practice Questions Answers Test with Solutions & More Shortcuts
average PRACTICE TEST [9 - EXERCISES]
model 1 basic average questions
model 2 average of consecutive numbers
model 3 twice, thrice, one third etc. of numbers
model 4 find nth average from 1st & last number
model 5 find new average from error
model 6 find average of excluded number
model 7 average on ages/weight
model 8 find monthly income
model 9 average on cricket/exam
Question : 6
In a 20 over match, the required run rate to win is 7.2. If the run rate is 6 at the end of the 15th over, the required run rate to win the match is
a) 13.2
b) 12
c) 1.2
d) 10.8
Answer »Answer: (d)
Total runs = 20 × 7.2 = 144
Total runs in 15 overs = 15 × 6 = 90
Runs to be scored in the next 5 overs = 144 – 90 = 54
∴ Required run-rate = $54/5$ = 10.8
Question : 7
In the first 10 overs of a cricket game, the run rate was only 3.2. The run rate in the remaining 40 overs to reach the target of 282 runs is
a) 6.3
b) 6.5
c) 6.4
d) 6.25
Answer »Answer: (d)
Total runs scored in first 10 overs = 3.2 × 10 = 32
Runs to be scored in remaining 40 overs = 282 – 32 = 250
∴ Required run–rate = $250/40$ = 6.25
Question : 8 [SSC CGL Tier-II 2013]
Sachin Tendulkar has a certain average for 11 innings. In the 12th innings he scores 120 runs and thereby increases his average by 5 runs. His new average is
a) 62
b) 66
c) 60
d) 65
Answer »Answer: (d)
Sachin’s new average = x runs
Total runs in 11 innings = 11 (x – 5)
∴ 11 (x – 5) + 120 = 12x
∴ 12x – 11x = 65
∴ x = 65 runs
Question : 9 [SSC CHSL 2012]
A cricketer has a mean score of 60 runs in 10 innings. Find out how many runs are to be scored in the eleventh innings to raise the mean score to 62?
a) 82
b) 81
c) 83
d) 80
Answer »Answer: (a)
Required runs = 60 + 11 × 2 = 82 runs
Aliter : Using Rule 18,
If in the group of N persons, a new person comes at the place of a person of 'T’ years, so that average age,
increases by 't’ years
Then, the age of the new person = T + N.t.
Here, T = 60, N = (10 + 1) t = 62 – 60 = 2
Required Runs = T + Nt
= 60 + 11 × 2 = 82
Question : 10 [SSC CPO 2008]
A cricketer has a certain average of runs for his 8 innings. In the ninth innings, he scores 100 runs, thereby increases his average by 9 runs. His new average of runs is
a) 24
b) 32
c) 20
d) 28
Answer »Answer: (d)
Let the average of runs of the cricketer in 8 innings be x .
According to the question,
${8x+100}/9$=x+9
⇒ 8x + 100 = 9x + 81
⇒ x = 100 – 81 = 19
∴ New average of runs = 19 + 9 = 28
IMPORTANT quantitative aptitude EXERCISES
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Basic Average Questions Practice Test, Shortcuts, Tricks, PDF »
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New Average Aptitude MCQ Average of Consecutive Numbers »
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Top 99+ Average Aptitude: Twice, One Third of Numbers MCQ »
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New +99 Average Aptitude MCQ Find nth Average of Numbers »
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99+ Average Aptitude Find New Average from Error MCQ Test »
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Top 99+ Aptitude MCQ Test on Average With Excluded Number »
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Top 99+ Aptitude Average on Ages & Weights MCQ Test Quiz »
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Top Aptitude Average MCQ Find Monthly Income for Average »
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Top 149+ Aptitude Average on Cricket & Exam MCQ Test Quiz »
model 9 average on cricket/exam Shortcuts »
Click to Read...model 9 average on cricket/exam Online Quiz
Click to Start..average Shortcuts and Techniques with Examples
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model 1 basic average questions
Defination & Shortcuts … -
model 2 average of consecutive numbers
Defination & Shortcuts … -
model 3 twice, thrice, one third etc. of numbers
Defination & Shortcuts … -
model 4 find nth average from 1st & last number
Defination & Shortcuts … -
model 5 find new average from error
Defination & Shortcuts … -
model 6 find average of excluded number
Defination & Shortcuts … -
model 7 average on ages/weight
Defination & Shortcuts … -
model 8 find monthly income
Defination & Shortcuts … -
model 9 average on cricket/exam
Defination & Shortcuts …
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