model 9 average on cricket/exam Practice Questions Answers Test with Solutions & More Shortcuts

Question : 6

In a 20 over match, the required run rate to win is 7.2. If the run rate is 6 at the end of the 15th over, the required run rate to win the match is

a) 13.2

b) 12

c) 1.2

d) 10.8

Answer: (d)

Total runs = 20 × 7.2 = 144

Total runs in 15 overs = 15 × 6 = 90

Runs to be scored in the next 5 overs = 144 – 90 = 54

∴ Required run-rate = $54/5$ = 10.8

Question : 7

In the first 10 overs of a cricket game, the run rate was only 3.2. The run rate in the remaining 40 overs to reach the target of 282 runs is

a) 6.3

b) 6.5

c) 6.4

d) 6.25

Answer: (d)

Total runs scored in first 10 overs = 3.2 × 10 = 32

Runs to be scored in remaining 40 overs = 282 – 32 = 250

∴ Required run–rate = $250/40$ = 6.25

Question : 8 [SSC CGL Tier-II 2013]

Sachin Tendulkar has a certain average for 11 innings. In the 12th innings he scores 120 runs and thereby increases his average by 5 runs. His new average is

a) 62

b) 66

c) 60

d) 65

Answer: (d)

Sachin’s new average = x runs

Total runs in 11 innings = 11 (x – 5)

∴ 11 (x – 5) + 120 = 12x

∴ 12x – 11x = 65

∴ x = 65 runs

Question : 9 [SSC CHSL 2012]

A cricketer has a mean score of 60 runs in 10 innings. Find out how many runs are to be scored in the eleventh innings to raise the mean score to 62?

a) 82

b) 81

c) 83

d) 80

Answer: (a)

Required runs = 60 + 11 × 2 = 82 runs

Aliter : Using Rule 18,

If in the group of N persons, a new person comes at the place of a person of 'T’ years, so that average age,

increases by 't’ years

Then, the age of the new person = T + N.t.

Here, T = 60, N = (10 + 1) t = 62 – 60 = 2

Required Runs = T + Nt

= 60 + 11 × 2 = 82

Question : 10 [SSC CPO 2008]

A cricketer has a certain average of runs for his 8 innings. In the ninth innings, he scores 100 runs, thereby increases his average by 9 runs. His new average of runs is

a) 24

b) 32

c) 20

d) 28

Answer: (d)

Let the average of runs of the cricketer in 8 innings be x .

According to the question,

${8x+100}/9$=x+9

⇒ 8x + 100 = 9x + 81

⇒ x = 100 – 81 = 19

∴ New average of runs = 19 + 9 = 28

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