model 9 average on cricket/exam Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 9 EXERCISES

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Questions : In the first 10 overs of a cricket game, the run rate was only 3.2. The run rate in the remaining 40 overs to reach the target of 282 runs is

(a) 6.3

(b) 6.5

(c) 6.4

(d) 6.25

The correct answers to the above question in:

Answer: (d)

Total runs scored in first 10 overs = 3.2 × 10 = 32

Runs to be scored in remaining 40 overs = 282 – 32 = 250

∴ Required run–rate = $250/40$ = 6.25

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Question : 1

Sachin Tendulkar has a certain average for 11 innings. In the 12th innings he scores 120 runs and thereby increases his average by 5 runs. His new average is

a) 62

b) 66

c) 60

d) 65

Answer: (d)

Sachin’s new average = x runs

Total runs in 11 innings = 11 (x – 5)

∴ 11 (x – 5) + 120 = 12x

∴ 12x – 11x = 65

∴ x = 65 runs

Question : 2

A cricketer has a mean score of 60 runs in 10 innings. Find out how many runs are to be scored in the eleventh innings to raise the mean score to 62?

a) 82

b) 81

c) 83

d) 80

Answer: (a)

Required runs = 60 + 11 × 2 = 82 runs

Aliter : Using Rule 18,

If in the group of N persons, a new person comes at the place of a person of 'T’ years, so that average age,

increases by 't’ years

Then, the age of the new person = T + N.t.

Here, T = 60, N = (10 + 1) t = 62 – 60 = 2

Required Runs = T + Nt

= 60 + 11 × 2 = 82

Question : 3

A cricketer has a certain average of runs for his 8 innings. In the ninth innings, he scores 100 runs, thereby increases his average by 9 runs. His new average of runs is

a) 24

b) 32

c) 20

d) 28

Answer: (d)

Let the average of runs of the cricketer in 8 innings be x .

According to the question,

${8x+100}/9$=x+9

⇒ 8x + 100 = 9x + 81

⇒ x = 100 – 81 = 19

∴ New average of runs = 19 + 9 = 28

Question : 4

In a 20 over match, the required run rate to win is 7.2. If the run rate is 6 at the end of the 15th over, the required run rate to win the match is

a) 13.2

b) 12

c) 1.2

d) 10.8

Answer: (d)

Total runs = 20 × 7.2 = 144

Total runs in 15 overs = 15 × 6 = 90

Runs to be scored in the next 5 overs = 144 – 90 = 54

∴ Required run-rate = $54/5$ = 10.8

Question : 5

The batting average for 30 innings of a cricket player is 40 runs. His highest score exceeds his lowest score by 100 runs. If these two innings are not included, the average of the remaining 28 innings is 38 runs. The lowest score of the player is :

a) 18

b) 12

c) 15

d) 20

Answer: (a)

Lowest score = x

Highest score = x + 100

∴ 28 × 38 + x + x + 100 = 30 × 40

⇒ 1064 + 2x + 100 = 1200

⇒ 2x = 1200 – 1164 = 36

⇒ x = 18

Question : 6

The average of runs of a cricket player of 20 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4?

a) 114

b) 76

c) 116

d) 170

Answer: (c)

Total runs scored by the cricketer in 20 innings = 32 × 20 = 640

If the runs scored in 21st innings be x, then

640 + x = 21 × 36

⇒ 640 + x = 756

⇒ x = 756 – 640 = 116

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