model 10 reduced/increased price of an article Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (a)

Original price of rice = Rs.x per kg.

New price = ${80x}/100$ = Rs.${4x}/5$ per kg

According to the question,

$1200/{{4x}/5} – 1200/x$ = 5

${1200 × 5}/{4x} – 1200/x$ = 5

$1500/x – 1200/x$ = 5

$300/x$ = 5 ⇒ 5x = 300

$x = 300/5$ = Rs.60 per kg

New price of rice

= Rs.$({4 × 60}/5)$ per kg = Rs.48 per kg

Answer: (d)

If the C.P. of article be Rs.x, then

$x × (105 – {195}/2)$% = 12

$x × 15/200 = 12 ⇒ x = {12 × 200}/15$ = Rs.160

Answer: (d)

Selling price = 405 × 110% = Rs.445.50

Remaining apples = 10 – 1= 9 kg

Therefore, the remaining apples (per kg) cost

=$445.50/9$ = Rs.49.50

Answer: (d)

Due to fall in price, there is a saving of 20% of Rs.100 i.e., Rs.20.

With this amount the purchaser purchases 4 kg. of salt.

Reduced price of salt per kg = $20/4$ = Rs.5

Answer: (d)

Let the original rate = x per kg.

New rate = 85% of x = ${85x}/100 = {17x}/20$

Original quantity for Rs.240 = $240/x$

New quantity = 240 × $20/{17x} = 4800/{17x}$

$4800/{17x} – 240/x$ = 2

${4800 – 4080}/{17x}$ = 2

$720/{17x} = 2 ⇒ x = 720/{2 × 17}$

Original rate per kg = Rs.$720/34$

Reduced rate = Rs.${17x}/20$

= Rs.$(17/20 × 720/34)$ = Rs.18