model 2 gain lost percentage Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (b)

If the CP of A articles be equal to SP of B articles, then

Loss percent = ${B - A}/B × 100$

= ${16 - 10}/16 × 100 = 6/16 × 100$ = 37.5%

Using Rule 8,

Here, x = 10, y = 16

Loss % = $({y - x}/y) × 100$

= $({16 - 10}/16) × 100 = 600/16$ = 37.5%

Answer: (d)

Let the cost price of one table = x

Cost price of 15 tables = 15x

and cost price of 20 tables = 20x

According to the question Selling price of 20 tables

= cost price of 15 tables = 15x

Loss = 20x - 15x = 5x

Loss% = ${5x × 100}/{20x} = 25%$

Using Rule 8,

Here, x = 15, y = 20

Loss % = ${x - y}/y × 100$

= $({15 - 20}/20) × 100$

=${-5}/20 × 100 = -25%$

(–ve sign shows loss)

= 25%

Answer: (d)

Profit percent = ${400 - 320}/320 × 100$

= $80/320 × 100 = 25%$

Using Rule 8

Here, x = 400, y = 320

Gain % = $({x - y}/y) × 100$

= ${400 - 320}/320 × 100 =80/320 × 100 = 25%$

Answer: (c)

Let CP of each coconut be Rs.1.

CP of 2500 coconuts = Rs.2500

SP of 2500 coconuts = Rs.2750

Gain % = ${2750 - 2500}/2500 × 100$ = 10%

Using Rule 8,

Here, x = 2750, y = 2500

Gain % = $({x - y}/y) × 100$

= $({2750 - 2500}/2500) × 100$

= $250/2500 × 100$ = 10%

Answer: (d)

Using Rule 8,

Loss per cent = ${400 - 320}/400 × 100$

= $80/400 × 100 = 20%$

Answer: (c)

Let C.P. be Rs.1

C.P. of 3 articles = Rs.3 = S.P. of P. of 5 articles.

Loss% = $({5 - 3})/5 × 100$ = 2 × 20 = 40%

Using Rule 8,

Here, x = 3, y = 5

Loss % = $({x - y}/y) × 100$

$({3 - 5}/5) × 100$ = - 40%

(–ve sign shows loss)

= 40 %