Practice Gain lost percentage - quantitative aptitude Online Quiz (set-1) For All Competitive Exams

Q-1)   If the cost price of 50 oranges is equal to the selling price of 40 oranges, then the profit per cent is

(a)

(b)

(c)

(d)

Explanation:

Let the C.P. of one orange = 1

C.P. of 40 oranges = Rs.40

and S.P. of 40 oranges = Rs.50

Profit = (50 - 40) = Rs.10

Profit % = $10/40 × 100$ = 25%

Using Rule 8,

Here, x = 50, y = 40

Profit % = $({x - y}/y) × 100$

= $({50 - 40}/40) × 100$ = 25%

Q-2)   The selling price of 10 oranges is the cost price of 13 oranges. Then the profit percentage is

(a)

(b)

(c)

(d)

Explanation:

Let the CP of 1 orange = Rs.1

SP of 10 oranges = Rs.13

Gain percent = ${13 - 10}/10 × 100$ = 30%

Using Rule 8,

Here, x = 13, y = 10

Profit % = $({x - y}/y) × 100$

= $({13 - 10}/10) × 100 = 300/10$ = 30%

Q-3)   The cost price of 40 articles is the same as the selling price of 25 articles. Find the gain per cent.

(a)

(b)

(c)

(d)

Explanation:

Gain per cent

= ${40 - 25}/25 × 100 = 15/25 × 100 = 60%$

Using Rule 8,

Here, x = 40, y = 25

Gain % = $({x - y}/y) × 100$

= ${40 - 25}/25 × 100 = 15/25 × 100$ = 60%

Q-4)   The cost price of 36 books is equal to the selling price of 30 books. The gain per cent is :

(a)

(b)

(c)

(d)

Explanation:

Using Rule 8,

If cost price of 'x' articles is equal to selling price of 'y' articles,
then Selling Price = x, Cost Price = y
Hence, Profit or Loss% = ${x - y}/y × 100$

Required profit = ${36 - 30}/30 × 100$ = 20%

Q-5)   If the selling price of 10 articles is equal to the cost price of 11 articles, then the gain percent is

(a)

(b)

(c)

(d)

Explanation:

Let the C.P. of each article be Rs.1.

C.P. of 10 articles = Rs.10

and S.P. of 10 articles = Rs.11

Profit percent = ${11 - 10}/10 × 100$ = 10%

Using Rule 8,

Here, x = 11, y = 10

Profit % = $({x - y}/y) × 100$

= ${11 - 10}/10 × 100 = 100/10$ = 10%

Q-6)   A person sells 400 mangoes at the cost price of 320 mangoes. His percentage of loss is

(a)

(b)

(c)

(d)

Explanation:

Using Rule 8,

Loss per cent = ${400 - 320}/400 × 100$

= $80/400 × 100 = 20%$

Q-7)   If the cost price of 10 articles is equal to the selling price of 16 articles, then the loss per cent is

(a)

(b)

(c)

(d)

Explanation:

If the CP of A articles be equal to SP of B articles, then

Loss percent = ${B - A}/B × 100$

= ${16 - 10}/16 × 100 = 6/16 × 100$ = 37.5%

Using Rule 8,

Here, x = 10, y = 16

Loss % = $({y - x}/y) × 100$

= $({16 - 10}/16) × 100 = 600/16$ = 37.5%

Q-8)   If the cost price of 15 tables be equal to the selling price of 20 tables, the loss per cent is :

(a)

(b)

(c)

(d)

Explanation:

Let the cost price of one table = x

Cost price of 15 tables = 15x

and cost price of 20 tables = 20x

According to the question Selling price of 20 tables

= cost price of 15 tables = 15x

Loss = 20x - 15x = 5x

Loss% = ${5x × 100}/{20x} = 25%$

Using Rule 8,

Here, x = 15, y = 20

Loss % = ${x - y}/y × 100$

= $({15 - 20}/20) × 100$

=${-5}/20 × 100 = -25%$

(–ve sign shows loss)

= 25%

Q-9)   The cost price of 400 lemons is equal to the selling price of 320 lemons. Then the profit percent is

(a)

(b)

(c)

(d)

Explanation:

Profit percent = ${400 - 320}/320 × 100$

= $80/320 × 100 = 25%$

Using Rule 8

Here, x = 400, y = 320

Gain % = $({x - y}/y) × 100$

= ${400 - 320}/320 × 100 =80/320 × 100 = 25%$

Q-10)   The cost price of 20 oranges is same with selling price of 16 oranges. The profit percentage is

(a)

(b)

(c)

(d)

Explanation:

Gain per cent = ${20 - 16}/16 × 100 = 25%$

Using Rule 8,

Here, x = 20, y = 16

Gain % = $({x - y}/y) × 100$

= ${20 - 16}/16 × 100 = 4/16 × 100 = 25%$