model 2 gain lost percentage Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (c)

Let the CP of 1 apple = Rs.1

CP of 18 apples = Rs.18

SP of 18 apples = Rs.24

Gain percent = $6/18 × 100 = 100/3 = 33{1}/3%$

Using Rule 8,

Here, x = 24, y = 18

Gain % = $({x - y}/y) × 100$

= ${24 - 18}/18 × 100 = 6/18 × 100 = 33{1}/3%$

Answer: (a)

Let the C.P. of each article be Rs.1.

C.P. of 10 articles = Rs.10

and S.P. of 10 articles = Rs.11

Profit percent = ${11 - 10}/10 × 100$ = 10%

Using Rule 8,

Here, x = 11, y = 10

Profit % = $({x - y}/y) × 100$

= ${11 - 10}/10 × 100 = 100/10$ = 10%

Answer: (c)

Let C.P. be Rs.1

C.P. of 3 articles = Rs.3 = S.P. of P. of 5 articles.

Loss% = $({5 - 3})/5 × 100$ = 2 × 20 = 40%

Using Rule 8,

Here, x = 3, y = 5

Loss % = $({x - y}/y) × 100$

$({3 - 5}/5) × 100$ = - 40%

(–ve sign shows loss)

= 40 %

Answer: (c)

Percentage profit = ${18 - 16}/16 × 100$

= $25/2 = 12{1}/2$%

Using Rule 8,

Here, x = 18, y = 16

Gain % = $({x - y}/y) × 100$

= ${18 - 16}/16 × 100$

= $2/16 × 100 = 25/2 = 12{1}/2$%

Answer: (b)

Gain per cent

= ${40 - 25}/25 × 100 = 15/25 × 100 = 60%$

Using Rule 8,

Here, x = 40, y = 25

Gain % = $({x - y}/y) × 100$

= ${40 - 25}/25 × 100 = 15/25 × 100$ = 60%

Answer: (b)

Percentage profit = ${25 - 20}/20 × 100$ = 25%

Using Rule 8,

Here, x = 25, y = 20

Gain % = $({x - y}/y) × 100$

= ${25 - 20}/20 × 100 = 500/20$ = 25%