model 2 gain lost percentage Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (d)

Gain per cent = ${20 - 16}/16 × 100 = 25%$

Using Rule 8,

Here, x = 20, y = 16

Gain % = $({x - y}/y) × 100$

= ${20 - 16}/16 × 100 = 4/16 × 100 = 25%$

Answer: (c)

Let the C.P. of one orange = 1

C.P. of 40 oranges = Rs.40

and S.P. of 40 oranges = Rs.50

Profit = (50 - 40) = Rs.10

Profit % = $10/40 × 100$ = 25%

Using Rule 8,

Here, x = 50, y = 40

Profit % = $({x - y}/y) × 100$

= $({50 - 40}/40) × 100$ = 25%

Answer: (d)

If the CP of each article be Rs.1 then

CP of 4 articles = Rs.4

SP of 4 articles = Rs.5

Profit percent = ${5 - 4}/4 × 100 = 25%$

Using Rule 8,

Here, x = 5, y = 4

Profit % = $({x - y}/y) × 100$

= $({5 - 4}/4) × 100 = 100/4$ = 25%

Answer: (d)

Profit percent = ${400 - 320}/320 × 100$

= $80/320 × 100 = 25%$

Using Rule 8

Here, x = 400, y = 320

Gain % = $({x - y}/y) × 100$

= ${400 - 320}/320 × 100 =80/320 × 100 = 25%$

Answer: (d)

Let the cost price of one table = x

Cost price of 15 tables = 15x

and cost price of 20 tables = 20x

According to the question Selling price of 20 tables

= cost price of 15 tables = 15x

Loss = 20x - 15x = 5x

Loss% = ${5x × 100}/{20x} = 25%$

Using Rule 8,

Here, x = 15, y = 20

Loss % = ${x - y}/y × 100$

= $({15 - 20}/20) × 100$

=${-5}/20 × 100 = -25%$

(–ve sign shows loss)

= 25%

Answer: (b)

If the CP of A articles be equal to SP of B articles, then

Loss percent = ${B - A}/B × 100$

= ${16 - 10}/16 × 100 = 6/16 × 100$ = 37.5%

Using Rule 8,

Here, x = 10, y = 16

Loss % = $({y - x}/y) × 100$

= $({16 - 10}/16) × 100 = 600/16$ = 37.5%