model 2 gain lost percentage Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on profit & loss topic of quantitative aptitude

Questions : If the cost price of 15 tables be equal to the selling price of 20 tables, the loss per cent is :

(a) 20%

(b) 30%

(c) 37.5%

(d) 25%

The correct answers to the above question in:

Answer: (d)

Let the cost price of one table = x

Cost price of 15 tables = 15x

and cost price of 20 tables = 20x

According to the question Selling price of 20 tables

= cost price of 15 tables = 15x

Loss = 20x - 15x = 5x

Loss% = ${5x × 100}/{20x} = 25%$

Using Rule 8,

Here, x = 15, y = 20

Loss % = ${x - y}/y × 100$

= $({15 - 20}/20) × 100$

=${-5}/20 × 100 = -25%$

(–ve sign shows loss)

= 25%

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Read more gain lost percentage Based Quantitative Aptitude Questions and Answers

Question : 1

The cost price of 400 lemons is equal to the selling price of 320 lemons. Then the profit percent is

a) 15%

b) 20%

c) 40%

d) 25%

Answer: (d)

Profit percent = ${400 - 320}/320 × 100$

= $80/320 × 100 = 25%$

Using Rule 8

Here, x = 400, y = 320

Gain % = $({x - y}/y) × 100$

= ${400 - 320}/320 × 100 =80/320 × 100 = 25%$

Question : 2

A sold an article to B at 20% profit and B sold to C at 15% loss. If A sold it to C at the selling price of B, then A would make

a) 5% profit

b) 2% profit

c) 5% loss

d) 2% loss

Answer: (b)

C.P. of article for A = Rs. 100

A’s S.P. = ${100 × 120}/100$ = Rs. 120

B’s S.P. = ${120 × 85}/100$ = Rs. 102

= C.P. for C

Required profit percent = 2%

Question : 3

The cost price of 20 oranges is same with selling price of 16 oranges. The profit percentage is

a) 30%

b) 20%

c) 16%

d) 25%

Answer: (d)

Gain per cent = ${20 - 16}/16 × 100 = 25%$

Using Rule 8,

Here, x = 20, y = 16

Gain % = $({x - y}/y) × 100$

= ${20 - 16}/16 × 100 = 4/16 × 100 = 25%$

Question : 4

If the cost price of 10 articles is equal to the selling price of 16 articles, then the loss per cent is

a) 30%

b) 37.5%

c) 45%

d) 42.5%

Answer: (b)

If the CP of A articles be equal to SP of B articles, then

Loss percent = ${B - A}/B × 100$

= ${16 - 10}/16 × 100 = 6/16 × 100$ = 37.5%

Using Rule 8,

Here, x = 10, y = 16

Loss % = $({y - x}/y) × 100$

= $({16 - 10}/16) × 100 = 600/16$ = 37.5%

Question : 5

If the cost price of 10 articles is equal to the selling price of 9 articles, the gain or loss per cent is

a) 11$1/9$% profit

b) 7$6/17$% profit

c) 1$12/13$% loss

d) 11$1/9$% loss

Answer: (a)

Required profit per cent =${10 - 9}/9 × 100$

= $1/9 × 100 = 11{1}/ 9%$

Using Rule 8,

Here, x = 10, y = 9

Profit % = $({x - y}/y) × 100$

= $({10 - 9}/9) × 100$

= $1/9 × 100 = 11{1}/9%$

Question : 6

A coconut merchant finds that the cost price of 2750 coconuts is the same as the selling price of 2500 coconuts. The loss or gain per cent is

a) 5% loss

b) 15% loss

c) 10% gain

d) 20% gain

Answer: (c)

Let CP of each coconut be Rs.1.

CP of 2500 coconuts = Rs.2500

SP of 2500 coconuts = Rs.2750

Gain % = ${2750 - 2500}/2500 × 100$ = 10%

Using Rule 8,

Here, x = 2750, y = 2500

Gain % = $({x - y}/y) × 100$

= $({2750 - 2500}/2500) × 100$

= $250/2500 × 100$ = 10%

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GET profit & loss PRACTICE TEST EXERCISES

Model 1 Basic Concepts of C.P and S.P

model 2 gain lost percentage

model 3 gain/loss % with C.P/S.P

model 4 sold & brought

model 5 marked price

model 6 sold in circular path

model 7 sold at loss

model 8 two article sold in different rates

model 9 selling an article & interchanging its values

model 10 reduced/increased price of an article

model 11 ratio & partnership
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