Trigonometric Ratios & Identity Model Questions Set 1 Practice Questions Answers Test with Solutions & More Shortcuts

Trigonometric Ratios & Identities PRACTICE TEST [1 - EXERCISES]

Trigonometric Ratios & Identity Model Questions Set 1

Question : 11

What is ${\text"sec x"}/{\text"cot x + tan x"}$ equal to ?

a) cos x

b) sin x

c) tan x

d) cot x

Answer: (b)

${\text"sec x"}/{\text"cot x + tan x"}$

⇒ ${1/{\text"cos x"}}/{{\text"cos x"}/{\text"sin x"} + {\text"sin x"}/{\text"cos x"}}$

⇒ ${1/{\text"cos x"}}/{{cos^2 x + sin^2 x}/{\text"sin x cos x"}}$

⇒ $1/{(\text"cos x")}$ × cos x × sin x

⇒ sin x

Question : 12

What is the least value of (25 $cosec^2 x + sec^2$ x) ?

a) 36

b) 40

c) 26

d) 24

Answer: (a)

Min Value = $(√{25} + 1)^2$ = 36

Question : 13

If tan x = 1, 0 < x < 90°, then what is the value of 2 sin x cos x ?

a) 1

b) $1/2$

c) ${√3}/2$

d) $√3$

Answer: (a)

tan x = 1 = tan 45°

∴ x = 45°

2 sin x. cos x = 2 sin (45°) . cos (45°)

= 2 × $1/{√2} × 1/{√2}$ = 1

Question : 14

$({sin 35°}/{cos 55°})^2 - ({cos 55°}/{sin 35°})^2$ + 2sin 30° is equal to

a) 0

b) –1

c) 1

d) 2

Answer: (c)

$({sin 35°}/{cos 55°})^2 - ({cos 55°}/{sin 35°})^2$ + 2 sin 30° ....(1)

We know that

sin $({π}/2 - θ)$ = cos θ

⇒ sin (90 - 55°) = cos 55°

⇒ sin 35° = cos 55°

So from (1) we get

$({sin 35°}/{sin 35°})^2 - ({cos 55°}/{cos 55°})^2 + 2 × 1/2$

= $(1)^2 - (1)^2 + 1$

∴ Option (c) is correct.

Question : 15

Which one of the following is correct?

a) There is more than one θ with 0° < θ < 90° such that sin θ = a, where a is a real number.

b) There is only one q with 0° < θ < 90° such that sin θ = a, where a is a real number.

c) There is no θ with 0° < θ < 90° such that sin θ = a, where a is a real number.

d) There are exactly θ's with 0° < θ < 90° such that sin θ = a, where a is a real number.

Answer: (b)

It is true, for 0° < θ < 90°, there exist only one θ such sin θ = a.

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