Trigonometric Ratios & Identity Model Questions Set 1 Practice Questions Answers Test with Solutions & More Shortcuts
Trigonometric Ratios & Identities PRACTICE TEST [1 - EXERCISES]
Trigonometric Ratios & Identity Model Questions Set 1
Question : 11
What is ${\text"sec x"}/{\text"cot x + tan x"}$ equal to ?
a) cos x
b) sin x
c) tan x
d) cot x
Answer »Answer: (b)
${\text"sec x"}/{\text"cot x + tan x"}$
⇒ ${1/{\text"cos x"}}/{{\text"cos x"}/{\text"sin x"} + {\text"sin x"}/{\text"cos x"}}$
⇒ ${1/{\text"cos x"}}/{{cos^2 x + sin^2 x}/{\text"sin x cos x"}}$
⇒ $1/{(\text"cos x")}$ × cos x × sin x
⇒ sin x
Question : 12
What is the least value of (25 $cosec^2 x + sec^2$ x) ?
a) 36
b) 40
c) 26
d) 24
Answer »Answer: (a)
Min Value = $(√{25} + 1)^2$ = 36
Question : 13
If tan x = 1, 0 < x < 90°, then what is the value of 2 sin x cos x ?
a) 1
b) $1/2$
c) ${√3}/2$
d) $√3$
Answer »Answer: (a)
tan x = 1 = tan 45°
∴ x = 45°
2 sin x. cos x = 2 sin (45°) . cos (45°)
= 2 × $1/{√2} × 1/{√2}$ = 1
Question : 14
$({sin 35°}/{cos 55°})^2 - ({cos 55°}/{sin 35°})^2$ + 2sin 30° is equal to
a) 0
b) –1
c) 1
d) 2
Answer »Answer: (c)
$({sin 35°}/{cos 55°})^2 - ({cos 55°}/{sin 35°})^2$ + 2 sin 30° ....(1)
We know that
sin $({π}/2 - θ)$ = cos θ
⇒ sin (90 - 55°) = cos 55°
⇒ sin 35° = cos 55°
So from (1) we get
$({sin 35°}/{sin 35°})^2 - ({cos 55°}/{cos 55°})^2 + 2 × 1/2$
= $(1)^2 - (1)^2 + 1$
∴ Option (c) is correct.
Question : 15
Which one of the following is correct?
a) There is more than one θ with 0° < θ < 90° such that sin θ = a, where a is a real number.
b) There is only one q with 0° < θ < 90° such that sin θ = a, where a is a real number.
c) There is no θ with 0° < θ < 90° such that sin θ = a, where a is a real number.
d) There are exactly θ's with 0° < θ < 90° such that sin θ = a, where a is a real number.
Answer »Answer: (b)
It is true, for 0° < θ < 90°, there exist only one θ such sin θ = a.
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