type 6 si with ratios Practice Questions Answers Test with Solutions & More Shortcuts
simple interest PRACTICE TEST [6 - EXERCISES]
type 1 basic simple interest using formula
type 2 increase or decrease in interest rate
type 3 money multiples in ‘n’ years
type 4 difference & equality of si rate & years
type 5 si on ‘n’ years & ‘x/y ‘of sum
type 6 si with ratios
Question : 1 [SSC MTS 2011]
In a certain time, the ratio of a certain principal and the simple interest obtained from it are in the ratio 10 : 3 at 10% interest per annum. The number of years the money was invested is
a) 3 years
b) 1 year
c) 7 years
d) 5 years
Answer »Answer: (a)
Using Rule 1,
Time = $\text"S.I. × 100"/ \text"Principal × Rate"$
= $3/10 × 100/10$ = 3 years
Question : 2 [SSC CGL Prelim 2002]
A person lent Rs.5,000 partly at the rate of 4 per cent and partly at the rate of 5 per cent per annum simple interest. The total interest after 2 years is Rs.440. To find the sum of money lent at each of the above rates, Rs.5,000 is to be divided in the ratio :
a) 3 : 2
b) 4 : 5
c) 2 : 3
d) 5 : 4
Answer »Answer: (a)
Using Rule 1,
Let the sum of x be lent at the rate of 4% and (5000 - x) at the rate of 5%
${x × 4 × 2}/100 + {(5000 - x) × 5 × 2}/100$ = 440
8x + 50000 - 10x = 44000
2x = 50000 - 44000 = 6000
x = Rs.3000
Rs.(5000 - x) = Rs.(5000 - 3000) = Rs.2000
Now, Required ratio
= 3000 : 2000 = 3 : 2
Question : 3 [SSC CGL Tier-II 2016]
A sum of Rs. 4000 is lent out in two parts, one at 8% simple interest and the other at 10% simple interest. If the annual interest is Rs. 352, the sum lent at 8% is
a) Rs.2200
b) Rs.2900
c) Rs.3100
d) Rs.2400
Answer »Answer: (d)
Principal lent at 8% S.I. = Rs.x.
Principal lent at 10% S.I. = Rs.(4000 - x)
S.I. = $\text"Principal × Time × Rate"/100$
${x × 8}/100 + {(4000 - x) × 10}/100$ = 352
8x + 40000 - 10x = 35200
2x = 40000 - 35200 = 4800
x = $4800/2$ = Rs.2400
Question : 4 [SSC SO 2005]
A person borrows some money for 5 years and loan amount : total interest amount is 5 : 2. The ratio of loan amount : interest rate is equal to :
a) 2 : 1
b) 2 : 25
c) 25 : 2
d) 5 : 2
Answer »Answer: (c)
Required ratio = 5 : $2/5$ = 25 : 2
$\text"loan amount"/ \text"Interest amount" = 5/2$
Interest rate = $2/5$
[Since, ${P + I}/I = 5/2 ⇒ P/I + I = 5/2$
⇒ $P/I = 3/2, then I = 2/5$]
$ \text"loan amount"/ \text"Interest rate"$
= $5/{2/5}= 25/2$ or 25 : 2
Question : 5 [SSC CHSL 2012]
Rs.12,000 is divided into two parts so that the simple interest on the first part for 3 years at 12% per annum may be equal to the simple interest on the second part for 4$1/2$ years at 16% per annum. The ratio of the first part to the second part is
a) 1 : 2
b) 2 : 1
c) 3 : 2
d) 2 : 3
Answer »Answer: (b)
Using Rule 1,
First part = Rs. x and second part
= (12000 - x )
${x × 3 × 12}/100 = {(12000 - x) × 9 × 16}/200$
$x/{12000 - x} = {9 × 16 × 100}/{3 × 12 × 200}$
= $2/1$ = 2 : 1
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type 6 si with ratios Shortcuts »
Click to Read...type 6 si with ratios Online Quiz
Click to Start..simple interest Shortcuts and Techniques with Examples
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type 1 basic simple interest using formula
Defination & Shortcuts … -
type 2 increase or decrease in interest rate
Defination & Shortcuts … -
type 3 money multiples in ‘n’ years
Defination & Shortcuts … -
type 4 difference & equality of si rate & years
Defination & Shortcuts … -
type 5 si on ‘n’ years & ‘x/y ‘of sum
Defination & Shortcuts … -
type 6 si with ratios
Defination & Shortcuts …
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