model 1 basic average questions Practice Questions Answers Test with Solutions & More Shortcuts
average PRACTICE TEST [9 - EXERCISES]
model 1 basic average questions
model 2 average of consecutive numbers
model 3 twice, thrice, one third etc. of numbers
model 4 find nth average from 1st & last number
model 5 find new average from error
model 6 find average of excluded number
model 7 average on ages/weight
model 8 find monthly income
model 9 average on cricket/exam
Question : 21
The average income of 40 persons is Rs. 4200 and that of another 35 persons is Rs. 4000. The average income of the whole group is :
a) Rs.4106$2/3$
b) Rs.4108$1/3$
c) Rs.4106$1/3$
d) Rs.4100
Answer »Answer: (a)
Using Rule 2,
If the given observations (x) are occuring with certain frequency (A) then,
$Average = {A_1x_1+A_2x_2+...............+A_nx_n}/{x_1+x_2+......+x_n}$
where, $A_1, A_2, A_3, .......... A_n$ are frequenciesAverage income of whole group
= ${4200×40+4000×35}/75$
= ${168000+140000}/75$
= $308000/75$ =Rs. 4106$2/3$
Question : 22
The average of 1, 3, 5, 7, 9, 11, -------- to 25 terms is
a) 625
b) 50
c) 25
d) 125
Answer »Answer: (c)
Sum of first n odd natural numbers = $n^2$
∴ Their average = ${n^2}/n$ = n
∴ Required average = 25
because n = 25
Aliter : Using Rule 7,
Average = 25
Question : 23 [SSC CAPFs SI, CISF 2015]
The average weight of 3 men A, B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E whose weight is 3 kg more then that of D, replaces A, then the average weight of B, C, D and E becomes 79 kg. Then weight of A is
a) 75 kg.
b) 76 kg.
c) 74 kg.
d) 72 kg.
Answer »Answer: (a)
D’s weight = 80 × 4 – 84 × 3
= 320 – 252 = 68 kg.
E’s weight = 68 + 3 = 71 kg.
Total weight of (A + B + C + D + E)
= 84 × 3 + 68 + 71
= 252 + 68 + 71 = 391 kg.
Total weight of (B + C + D + E)
= 79 × 4 = 316 kg.
∴ A’s weight= 391 – 316 = 75 kg.
Question : 24 [SSC CGL Prelim 2003]
The average of 30 results is 20 and the average of other 20 results is 30. What is the average of all the results ?
a) 25
b) 50
c) 48
d) 24
Answer »Answer: (d)
Using Rule 10,
If the average of '$n_1$' numbers is $a_1$ and the average of '$n_2$' numbers is $a_2$, then average of total numbers $n_1$ and $n_2$ is
$Average = {n_1a_1 + n_2a_2}/{n_1 + n_2}$
Required average
= ${20×30+20×30}/{30+20}$
= ${600+600}/50$
= $1200/50$ = 24
Question : 25
If average of 20 observations $x_1 , x_2 , ....., x_20$ is y, then the average of $x_1 – 101, x_2 – 101, x_3 – 101, ....., x_20 –101$ is
a) 20y
b) 101y
c) y – 101
d) y – 20
Answer »Answer: (c)
Using Rule 2,
If the given observations (x) are occuring with certain frequency (A) then,
$Average = {A_1x_1+A_2x_2+...............+A_nx_n}/{x_1+x_2+......+x_n}$
where, $A_1, A_2, A_3, .......... A_n$ are frequencies
Required average
${x_1+x_2+…+x_20}/20$ = ${101×2}/20$
= y-101
IMPORTANT quantitative aptitude EXERCISES
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Basic Average Questions Practice Test, Shortcuts, Tricks, PDF »
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Top 149+ Aptitude Average on Cricket & Exam MCQ Test Quiz »
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model 1 basic average questions
Defination & Shortcuts … -
model 2 average of consecutive numbers
Defination & Shortcuts … -
model 3 twice, thrice, one third etc. of numbers
Defination & Shortcuts … -
model 4 find nth average from 1st & last number
Defination & Shortcuts … -
model 5 find new average from error
Defination & Shortcuts … -
model 6 find average of excluded number
Defination & Shortcuts … -
model 7 average on ages/weight
Defination & Shortcuts … -
model 8 find monthly income
Defination & Shortcuts … -
model 9 average on cricket/exam
Defination & Shortcuts …
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