model 1 basic average questions Practice Questions Answers Test with Solutions & More Shortcuts
average PRACTICE TEST [9 - EXERCISES]
model 1 basic average questions
model 2 average of consecutive numbers
model 3 twice, thrice, one third etc. of numbers
model 4 find nth average from 1st & last number
model 5 find new average from error
model 6 find average of excluded number
model 7 average on ages/weight
model 8 find monthly income
model 9 average on cricket/exam
Question : 6 [S.S.C. (CHSL) 2011]
a, b, c, d, e, f, g are consecutive even numbers. j, k, l, m, n are consecutive odd numbers. The average of all the numbers is
a) $3(\text"a+n"/2)$
b) $(\text"l+d"/2)$
c) $\text"a+b+m+n"/4$
d) $\text"j+c+n+g"/4$
Answer »Answer: (b)
According to the question consecutive even numbers = a, b, c, d, e, f, g
Consecutive odd numbers = j, k, l, m, n
Consecutive even number = 2, 4, 6, 8, 10, 12, 14
$\text"2+4+6+8+10+12+14"/7=56/7=8$ middle term
Consecutive odd numbers 1, 3, 5, 7, 9
$\text"1+3+5+7+9"/5=25/5$ middle term
Same as in the above situation.
Average of a, b, c, d, e, f, g = d
Average of j, k, l, m, n, = l
∴ Required average = ${d+l}/2$
Question : 7 [S.S.C. (CHSL) 2013]
The average of nine consecutive numbers is n. If the next two numbers are also included the new average w
a) increase by 2
b) remain the same
c) increase by 1.5
d) increase by 1
Answer »Answer: (d)
Given,
$\text"(a + a + 1 + a + 2 + a + 3 + a + 4 + a + 5 + a + 6 + a + 7 + a + 8)"/9 = n$
$=> \text"(9a + 36)"/9 = n$
=> a + 4 = n -------------------- ( 1 )
If the next 2 numbers are included , let new average = k
$\text"(a + a + 1 + a + 2 + a + 3 + a + 4 + a + 5 + a + 6 + a + 7 + a + 8 + a + 9 + a + 10)"/11 = k$
$\text"(11a + 55)"/11 = k$
a + 5 = k -------------------- ( 2 )
Subtracting ( 1 ) from ( 2 ) , we get :
a + 5 - a - 4 = k - n
=> k - n = 1
=> k = n + 1
Therefore the new average is n + 1
Question : 8 [S.S.C. (CGL) 2012]
The average of 5 consecutive integers starting with ‘m’ is n. What is the average of 6 consecutive integers starting with (m + 2) ?
a) $\text"2n+5"/2$
b) $n+2$
c) $n+3$
d) $\text"2n+9"/2$
Answer »Answer: (a)
According to the question let m = 1
∴ 5 consecutive integers are = 1,2,3,4,5
$\text"1+2+3+4+5"/5=n$
$n = 15/5=3$
6 consecutive integers starting with (m + 2) are = 3,4,5,6,7,8
∴$\text"3+4+5+6+7+8"/6=33/6=11/2$
Now check from option to put n = 3
While in Option :(a) $\text"2n+5"/2 = 11/2 $
Question : 9 [S.S.C. (CGL) 2013]
If a, b, c, d, e are five consecutive odd numbers, their average is
a) $5(a+4)$
b) $\text"abcde"/5$
c) $5(a+b+c+d+e)$
d) $a+4$
Answer »Answer: (d)
Question : 10
The average monthly income (in ₨) of certain agricultural workers is S and that of other workers is T. The number of agricultural workers is 11 times that of other workers. Then, the average monthly income (in ₨) of all the workers is :
a) $\text"S+11T"/12$
b) $\text"S+T"/12$
c) $\text"11S+T"/12$
d) $1/\text"11S"+T$
Answer »Answer: (c)
IMPORTANT quantitative aptitude EXERCISES
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Basic Average Questions Practice Test, Shortcuts, Tricks, PDF »
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New Average Aptitude MCQ Average of Consecutive Numbers »
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Top 99+ Average Aptitude: Twice, One Third of Numbers MCQ »
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New +99 Average Aptitude MCQ Find nth Average of Numbers »
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99+ Average Aptitude Find New Average from Error MCQ Test »
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Top 99+ Aptitude MCQ Test on Average With Excluded Number »
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Top 99+ Aptitude Average on Ages & Weights MCQ Test Quiz »
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Top Aptitude Average MCQ Find Monthly Income for Average »
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Top 149+ Aptitude Average on Cricket & Exam MCQ Test Quiz »
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model 1 basic average questions
Defination & Shortcuts … -
model 2 average of consecutive numbers
Defination & Shortcuts … -
model 3 twice, thrice, one third etc. of numbers
Defination & Shortcuts … -
model 4 find nth average from 1st & last number
Defination & Shortcuts … -
model 5 find new average from error
Defination & Shortcuts … -
model 6 find average of excluded number
Defination & Shortcuts … -
model 7 average on ages/weight
Defination & Shortcuts … -
model 8 find monthly income
Defination & Shortcuts … -
model 9 average on cricket/exam
Defination & Shortcuts …
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