model 5 find new average from error Practice Questions Answers Test with Solutions & More Shortcuts

Question : 6 [SSC CHSL 2012]

The average of seven numbers is 18. If one of the number is 17 and if it is replaced by 31, then the average becomes :

a) 19.5

b) 21.5

c) 21

d) 20

Answer: (d)

Difference = 31 – 17 = 14

∴ Required average = 18 +$14/7$ = 20

Aliter : Using Rule 26,

If average of n numbers is m later on it was found that a number 'a’ was misread as 'b’.

The correct average will be = m +${\text"(a-b)"}/ \text"n"$.

Here, n = 7, m = 18

a = 31, b = 17

New Average = m + ${\text"(a - b)"}/\text"n"$

= 18 +${(31 – 17)}/7$

= 18 +$14/7$

= 18 + 2 = 20

Question : 7 [SSC CPO 2011]

Mean of 10 numbers is 30. Later on it was observed that numbers 15, 23 are wrongly taken as 51, 32. The correct mean is

a) 32

b) 25.5

c) 34·5

d) 30

Answer: (b)

Difference = 15 + 23 – 51 – 32 = –45

∴ Correct average = 30 -$45/10$ = 25.5

Aliter : Using Rule 27,

The correct average = m +${\text"(a+b-p-q)"}/ \text"n"$.

Here, n = 10, m = 30

a = 15, b = 23

p = 51, q = 32

Correct Average

= m + ${\text"(a + b - p - q)"}/ \text"n"n$

= 30 + ${(15 + 23 - 51 – 32)}/10$

= 30 + $({38-83}/10)$

= 30 - $45/10$

= 30 – 4.5 = 25.5

Question : 8

The mean value of 20 observations was found to be 75, but later on it was detected that 97 was misread as 79. Find the correct mean.

a) 75.8

b) 75.7

c) 75.6

d) 75.9

Answer: (d)

Difference = 97 – 79 = 18

True average = 75 + $18/20$ = 75.9

Aliter : Using Rule 26,

If average of n numbers is m later on it was found that a number 'a’ was misread as 'b’.

The correct average will be = m +${\text"(a-b)"}/ \text"n"$.

Here, n = 20, m = 75

a = 97, b = 79

Correct mean = m + ${\text"(a - b)"}/\text"n"$

= 75 +${(97 -79)}/20$

= 75 +$18/20$

= 75 + 0.9 = 75.9

Question : 9

There are 50 students in a class. One of them weighing 50 kg goes away and a new student joins. By this the average weight of the class increases by $1/2$ kg. The weight of the new student is :

a) 72 kg

b) 70 kg

c) 76 kg

d) 75 kg

Answer: (d)

Total weight increased =$1/2$ × 50 = 25 kg.

∴ Weight of the new man = 50 + 25 = 75 kg.

Aliter : Using Rule 18,The age of the new person = T + N.t.

Here, N = 50, T = 50, t = $1/2$

Weight of New boy = T + Nt

= 50 + 50 × $1/2$ = 75 kg.

Question : 10 [SSC CGL Prelim 2000]

The average weight of 20 students in a class is increased by 0.75 kg when one of the students weighing 30 kg is replaced by a new student. Weight of the new student (in kg) is :

a) 40

b) 35

c) 50

d) 45

Answer: (d)

Required answer = 30 + 20 × 0.75

= 30 kg + 15 kg = 45 kg

Aliter : Using Rule 18,

If in the group of N persons, a new person comes at the place of a person of 'T’ years, so that average age,

increases by 't’ years

Then, the age of the new person = T + N.t.

Here, N = 20, T = 30, t = 0.75

Weight of New student = T + Nt

= 30 + 20 × 0.75

= 30 + 15 = 45 kg

IMPORTANT quantitative aptitude EXERCISES

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