model 5 find new average from error Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 9 EXERCISES
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Basic Average Questions Practice Test, Shortcuts, Tricks, PDF »
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New Average Aptitude MCQ Average of Consecutive Numbers »
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Top 99+ Average Aptitude: Twice, One Third of Numbers MCQ »
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New +99 Average Aptitude MCQ Find nth Average of Numbers »
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99+ Average Aptitude Find New Average from Error MCQ Test »
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Top 99+ Aptitude MCQ Test on Average With Excluded Number »
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Top 99+ Aptitude Average on Ages & Weights MCQ Test Quiz »
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Top Aptitude Average MCQ Find Monthly Income for Average »
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Top 149+ Aptitude Average on Cricket & Exam MCQ Test Quiz »
The following question based on average topic of quantitative aptitude
(a) 32
(b) 25.5
(c) 34·5
(d) 30
The correct answers to the above question in:
Answer: (b)
Difference = 15 + 23 – 51 – 32 = –45
∴ Correct average = 30 -$45/10$ = 25.5
Aliter : Using Rule 27,
The correct average = m +${\text"(a+b-p-q)"}/ \text"n"$.
Here, n = 10, m = 30
a = 15, b = 23
p = 51, q = 32
Correct Average
= m + ${\text"(a + b - p - q)"}/ \text"n"n$
= 30 + ${(15 + 23 - 51 – 32)}/10$
= 30 + $({38-83}/10)$
= 30 - $45/10$
= 30 – 4.5 = 25.5
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Read more new average from error Based Quantitative Aptitude Questions and Answers
Question : 1
The mean value of 20 observations was found to be 75, but later on it was detected that 97 was misread as 79. Find the correct mean.
a) 75.8
b) 75.7
c) 75.6
d) 75.9
Answer »Answer: (d)
Difference = 97 – 79 = 18
True average = 75 + $18/20$ = 75.9
Aliter : Using Rule 26,
If average of n numbers is m later on it was found that a number 'a’ was misread as 'b’.
The correct average will be = m +${\text"(a-b)"}/ \text"n"$.
Here, n = 20, m = 75
a = 97, b = 79
Correct mean = m + ${\text"(a - b)"}/\text"n"$
= 75 +${(97 -79)}/20$
= 75 +$18/20$
= 75 + 0.9 = 75.9
Question : 2
There are 50 students in a class. One of them weighing 50 kg goes away and a new student joins. By this the average weight of the class increases by $1/2$ kg. The weight of the new student is :
a) 72 kg
b) 70 kg
c) 76 kg
d) 75 kg
Answer »Answer: (d)
Total weight increased =$1/2$ × 50 = 25 kg.
∴ Weight of the new man = 50 + 25 = 75 kg.
Aliter : Using Rule 18,The age of the new person = T + N.t.
Here, N = 50, T = 50, t = $1/2$
Weight of New boy = T + Nt
= 50 + 50 × $1/2$ = 75 kg.
Question : 3
The average weight of 20 students in a class is increased by 0.75 kg when one of the students weighing 30 kg is replaced by a new student. Weight of the new student (in kg) is :
a) 40
b) 35
c) 50
d) 45
Answer »Answer: (d)
Required answer = 30 + 20 × 0.75
= 30 kg + 15 kg = 45 kg
Aliter : Using Rule 18,
If in the group of N persons, a new person comes at the place of a person of 'T’ years, so that average age,
increases by 't’ years
Then, the age of the new person = T + N.t.
Here, N = 20, T = 30, t = 0.75
Weight of New student = T + Nt
= 30 + 20 × 0.75
= 30 + 15 = 45 kg
Question : 4
The average of seven numbers is 18. If one of the number is 17 and if it is replaced by 31, then the average becomes :
a) 19.5
b) 21.5
c) 21
d) 20
Answer »Answer: (d)
Difference = 31 – 17 = 14
∴ Required average = 18 +$14/7$ = 20
Aliter : Using Rule 26,
If average of n numbers is m later on it was found that a number 'a’ was misread as 'b’.
The correct average will be = m +${\text"(a-b)"}/ \text"n"$.
Here, n = 7, m = 18
a = 31, b = 17
New Average = m + ${\text"(a - b)"}/\text"n"$
= 18 +${(31 – 17)}/7$
= 18 +$14/7$
= 18 + 2 = 20
Question : 5
The average of 18 observations is recorded as 124. Later it was found that two observations with values 64 and 28 were entered wrongly as 46 and 82. Find the correct average of the 18 observations.
a) 122
b) 111$7/9$
c) 137$3/9$
d) 123
Answer »Answer: (a)
Difference in observations
= 64 + 28 – 46 – 82 = – 36
∴ Correct average = 124 -$36/18$ = 122
Question : 6
The mean of 20 items is 47. Later it is found that the item 62 is wrongly written as 26. Find the correct mean.
a) 47·7
b) 48·8
c) 46·6
d) 49·9
Answer »Answer: (b)
Difference = 62 – 26 = 36
∴ Required average = 47 +$36/20$ = 47 + 1.8 = 48.8
Aliter : Using Rule 26,
The correct average will be = m +${\text"(a-b)"}/ \text"n"$.
Here, n = 20, m = 47
a = 62, b = 26
Correct Average = m + ${\text"(a - b)"}/\text"n"$
= 47 + ${(62 – 26)}/20$
= 47+$36/20$
= 47 + 1.8 = 48.8
GET average PRACTICE TEST EXERCISES
model 1 basic average questions
model 2 average of consecutive numbers
model 3 twice, thrice, one third etc. of numbers
model 4 find nth average from 1st & last number
model 5 find new average from error
model 6 find average of excluded number
model 7 average on ages/weight
model 8 find monthly income
model 9 average on cricket/exam
average Shortcuts and Techniques with Examples
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model 1 basic average questions
Defination & Shortcuts … -
model 2 average of consecutive numbers
Defination & Shortcuts … -
model 3 twice, thrice, one third etc. of numbers
Defination & Shortcuts … -
model 4 find nth average from 1st & last number
Defination & Shortcuts … -
model 5 find new average from error
Defination & Shortcuts … -
model 6 find average of excluded number
Defination & Shortcuts … -
model 7 average on ages/weight
Defination & Shortcuts … -
model 8 find monthly income
Defination & Shortcuts … -
model 9 average on cricket/exam
Defination & Shortcuts …
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