model 6 find average of excluded number Practice Questions Answers Test with Solutions & More Shortcuts
average PRACTICE TEST [9 - EXERCISES]
model 1 basic average questions
model 2 average of consecutive numbers
model 3 twice, thrice, one third etc. of numbers
model 4 find nth average from 1st & last number
model 5 find new average from error
model 6 find average of excluded number
model 7 average on ages/weight
model 8 find monthly income
model 9 average on cricket/exam
Question : 11 [SSC CPO 2016]
The average of five numbers is 7. If three new numbers would be added, then the new average comes out to be 8.5. What is the average of those three new numbers?
a) 10.5
b) 11
c) 9
d) 11.5
Answer »Answer: (b)
Sum of three new numbers = 8 × 8.5 – 7 × 5
= 68 – 35 = 33
∴ Required average = $33/3$ = 11
Question : 12 [SSC CHSL 2012]
If the mean of 4 observations is 20, when a constant 'C’ is added to each observation, the mean becomes 22. The value of C is :
a) –2
b) 2
c) 6
d) 4
Answer »Answer: (b)
4C = 22 × 4 – 20 × 4 = 88 – 80 = 8
⇒ C = $8/4$ = 2
Question : 13
The average weight of 12 parcels is 1.8 kg. Addition of another new parcel reduces the average weight by 50 g. What is the weight of the new parcel ?
a) 1.10 kg
b) 1.15 kg
c) 1.50 kg
d) 1.01 kg
Answer »Answer: (b)
Total weight 12 parcels = 12 × 1.8 = 21.6 kg.
New average of 13 parcels = 1.8 – 0.05 = 1.75 kg.
Total weight of 13 parcels = 13 × 1.75 = 22.75 kg.
∴ Weight of new parcel = 22.75 – 21.6 = 1.15 kg.
Aliter : Using Rule 18,
( If in the group of N persons, a new person comes at the place of a person of 'T’ years, so that average age,
increases by 't’ years
Then, the age of the new person = T + N.t. )
Here, T = 1.8, N= (12 + 1) = 13, t = $50/1000$ = .05
Weight of new parcel = T – Nt
= 1.8 – 13 × 0.05
= 1.8 – 0.65 = 1.15 kg
Question : 14
The average of five numbers is 27. If one number is excluded, the average becomes 25. The excluded number is :
a) 27
b) 30
c) 25
d) 35
Answer »Answer: (d)
Total sum of five numbers = 27 × 5 = 135
Total sum of four numbers = 25 × 4 = 100
∴ Required number = 135 – 100 = 35
Question : 15 [SSC CGL Tier-I 2013]
The average of 50 numbers is 38. If two numbers namely 45 and 55 are discarded, the average of the remaining numbers is :
a) 32.5
b) 37.5
c) 35
d) 36
Answer »Answer: (b)
Required average = ${38 × 50 – 45 – 55}/48$
= $1800/48$ = 37.5
IMPORTANT quantitative aptitude EXERCISES
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Basic Average Questions Practice Test, Shortcuts, Tricks, PDF »
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New Average Aptitude MCQ Average of Consecutive Numbers »
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Top 99+ Average Aptitude: Twice, One Third of Numbers MCQ »
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New +99 Average Aptitude MCQ Find nth Average of Numbers »
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99+ Average Aptitude Find New Average from Error MCQ Test »
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Top 99+ Aptitude MCQ Test on Average With Excluded Number »
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Top 99+ Aptitude Average on Ages & Weights MCQ Test Quiz »
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Top Aptitude Average MCQ Find Monthly Income for Average »
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Top 149+ Aptitude Average on Cricket & Exam MCQ Test Quiz »
model 6 find average of excluded number Shortcuts »
Click to Read...model 6 find average of excluded number Online Quiz
Click to Start..average Shortcuts and Techniques with Examples
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model 1 basic average questions
Defination & Shortcuts … -
model 2 average of consecutive numbers
Defination & Shortcuts … -
model 3 twice, thrice, one third etc. of numbers
Defination & Shortcuts … -
model 4 find nth average from 1st & last number
Defination & Shortcuts … -
model 5 find new average from error
Defination & Shortcuts … -
model 6 find average of excluded number
Defination & Shortcuts … -
model 7 average on ages/weight
Defination & Shortcuts … -
model 8 find monthly income
Defination & Shortcuts … -
model 9 average on cricket/exam
Defination & Shortcuts …
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