model 2 average of consecutive numbers Practice Questions Answers Test with Solutions & More Shortcuts

average PRACTICE TEST [9 - EXERCISES]

model 1 basic average questions

model 2 average of consecutive numbers

model 3 twice, thrice, one third etc. of numbers

model 4 find nth average from 1st & last number

model 5 find new average from error

model 6 find average of excluded number

model 7 average on ages/weight

model 8 find monthly income

model 9 average on cricket/exam

average Important Formulas, Rules, Concepts & Shortcuts

Question : 16 [SSC CGL Tier-II 2016]

The average of 7 consecutive numbers is 20. The largest of these numbers is

a) 26

b) 24

c) 23

d) 20

Shortcut »

Answer: (c)

Average of 7 consecutive numbers = 20

∴ Fourth number = 20

∴ Largest number = 20 + 3 = 23

Question : 17 [SSC CGL Tier-II 2016]

The sum of three consecutive even numbers is 28 more than the average of these three numbers. Then the smallest of these three numbers is

a) 16

b) 14

c) 12

d) 6

Shortcut »

Answer: (c)

Let three consecutive even numbers be x, x + 2 and x + 4. According to the question,

(x + x + 2 + x + 4) – ${x+x+2+x+4}/3$= 28

⇒ (3x + 6) – ${3x+6}/3$ = 28

⇒ (3x + 6) – (x + 2) = 28

⇒ 3x + 6 – x – 2 = 28

⇒ 2x + 4 = 28

⇒ 2x = 28 – 4 = 24

⇒ x = $24/2$ = 12

Question : 18 [SSC CPO 2003]

The average of first nine prime numbers is

a) 11$1/9$

b) 11$2/9$

c) 11

d) 9

Shortcut »

Answer: (a)

Using Rule 1,

Average of numbers = ${x_1+x_2+…+x_n}/n$

The required average

=${2+3+5+7+11+13+17+19+23}/9$

=$100/9$ = 11 $1/9$

Question : 19 [SSC CHSL 2017]

The average of 25 consecutive odd integers is 55. The highest of these integers is

a) 109

b) 155

c) 105

d) 79

Shortcut »

Answer: (d)

Average of 25 consecutive odd numbers = 55

∴ Mid number i.e. 13th number = 55

∴ 25th number = 55 + 2 × 12

= 55 + 24 = 79

Question : 20 [SSC CGL 2013]

The average of the first nine integral multiples of 3 is

a) 18

b) 15

c) 12

d) 21

Shortcut »

Answer: (b)

Required average

= ${3(1+2+3+…+9)}/9$

= ${9×10}/{2×3}$ = 15

Aliter : Using Rule 9,

Here, n = 9, x = 3

Average = x$({1+n}/2)$

= 3$({1+9}/2)$ = 15

IMPORTANT quantitative aptitude EXERCISES

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