model 2 average of consecutive numbers Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 9 EXERCISES

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The following question based on average topic of quantitative aptitude

Questions : The average of 7 consecutive numbers is 20. The largest of these numbers is

(a) 26

(b) 24

(c) 23

(d) 20

The correct answers to the above question in:

Answer: (c)

Average of 7 consecutive numbers = 20

∴ Fourth number = 20

∴ Largest number = 20 + 3 = 23

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Read more consecutive numbers Based Quantitative Aptitude Questions and Answers

Question : 1

The sum of three consecutive even numbers is 28 more than the average of these three numbers. Then the smallest of these three numbers is

a) 16

b) 14

c) 12

d) 6

Answer: (c)

Let three consecutive even numbers be x, x + 2 and x + 4. According to the question,

(x + x + 2 + x + 4) – ${x+x+2+x+4}/3$= 28

⇒ (3x + 6) – ${3x+6}/3$ = 28

⇒ (3x + 6) – (x + 2) = 28

⇒ 3x + 6 – x – 2 = 28

⇒ 2x + 4 = 28

⇒ 2x = 28 – 4 = 24

⇒ x = $24/2$ = 12

Question : 2

The average of first nine prime numbers is

a) 11$1/9$

b) 11$2/9$

c) 11

d) 9

Answer: (a)

Using Rule 1,

Average of numbers = ${x_1+x_2+…+x_n}/n$

The required average

=${2+3+5+7+11+13+17+19+23}/9$

=$100/9$ = 11 $1/9$

Question : 3

The average of 25 consecutive odd integers is 55. The highest of these integers is

a) 109

b) 155

c) 105

d) 79

Answer: (d)

Average of 25 consecutive odd numbers = 55

∴ Mid number i.e. 13th number = 55

∴ 25th number = 55 + 2 × 12

= 55 + 24 = 79

Question : 4

The average of three consecutive odd numbers is 12 more than one third of the first of these numbers. What is the last of the three numbers ?

a) Data inadequate

b) 19

c) 17

d) 15

Answer: (b)

If the smallest number be x, then

$x/3$+12 = x+2

⇒ x + 36 = 3x + 6

⇒ 3x – x = 36 – 6

⇒ 2x = 30 ⇒ x = 15

∴ Third number = 15 + 4 = 19

Question : 5

The average of 7 consecutive numbers is 20. The largest of these numbers is :

a) 20

b) 22

c) 23

d) 24

Answer: (c)

Average of 7 consecutive numbers is 20.

Since the numbers are consecutive, they form an arithmetic series with common difference 1.

Since, 7 is odd, 20 must be the middle number.

We can write the series as below,

17, 18, 19, 20, 21, 22, 23

∴ The largest of these numbers is 23.

Question : 6

The average of 5 consecutive integers starting with ‘m’ is n. What is the average of 6 consecutive integers starting with (m + 2) ?

a) ${2n+9}/2$

b) (n+3)

c) (n+2)

d) ${2n+5}/2$

Answer: (d)

m + m + 1 + m + 2 + m + 3 + m + 4 = 5n

⇒ 5m + 10 = 5n

⇒ m + 2 = n ....(i)

Required average = ${m+2+m+3+m+4+m+5+m+6+m+7}/6$

= ${6m+27}/6$

= ${2m+9}/2$ = ${2(n-2)+9}/2$= ${2n+5}/2$ By (i) [m = n – 2]

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