model 7 average on ages/weight Practice Questions Answers Test with Solutions & More Shortcuts

Question : 31 [SSC CHSL 2012]

Average age of 8 men is increased by 3 years when two of them whose age are 30 and 34 years are replaced by 2 persons. What is the average age of the 2 persons ?

a) 32 years

b) 24 years

c) 48 years

d) 44 years

Answer: (d)

Sum of the age of two new persons

= 30 + 34 + 3 × 8 = 88 years

∴ Required average = $88/2$ = 44 years

Question : 32 [SSC DEO 2008]

The average age of group of 20 girls is 15 years and that of another group of 25 boys it is 24 years. The average age of the two groups mixed together is

a) 20 years

b) 19.5 years

c) 21.5 years

d) 21 years

Answer: (a)

Required average age = $({20 × 15 + 25 × 24}/{20 + 25})$years

= $({300 + 600}/45)$years

= $(900/45)$ years = 20 years

Question : 33 [SSC SO 2003]

There are 30 students in a class. The average age of first 10 students is 12.5 years. The average age of the remaining 20 students is 13.1 years. The average age (in years) of the students of the whole class is

a) 12.7 years

b) 12.5 years

c) 12.9 years

d) 12.8 years

Answer: (c)

Using Rule 10,

( If the average of 'n1 ’ numbers is a1 and the average of 'n2 ’ numbers is a2 , then average of total numbers n1 and n2 is

Average = ${n_1a_1 + n_2a_2}/{n_1 + n_2}$ )

Average age = ${10 × 12.5 + 20 × 13.1}/{10+20}$

= ${125+262}/30$ =12.9 years

Question : 34

The average age of 30 boys in a class is 15 years. One boy, aged 20 years, left the class, but two new boys came in his place whose age differ by 5 years. If the average age of all the boys now in the class becomes 15 years, the age of the younger newcomer is :

a) 15 years

b) 20 years

c) 8 years

d) 10 years

Answer: (a)

Total age of 30 boys = 30 × 15 = 450 years

One boy, aged 20 years, left the class

Now, total age of 29 boys = 450 – 20 = 430 years

Again, two new boys join the class

Then, the total age of 31 boys = 15 × 31 = 465 years

∴ Age of two new boys = 465 – 430 = 35 years

Let the individual age of two boys be x and y years

∴ x + y = 35

x – y = 5 (According to the question)

∴ 2x = 40

x = $40/2$ = 20 years

∴ y = 15 years

∴ Age of the younger new comer = 15 years

Question : 35

The average age of a family of 10 members is 20 years. If the age of the youngest member of the family is 10 years, then the average age of the members of the family just before the birth of the youngest member was approximately

a) 12.5 years

b) 27.14 years

c) 11$1/9$ years

d) 14.28 years

Answer: (c)

Sum of the present age of 10 members

= 20 × 10 = 200 years

Total age of 9 members, 10 years ago = 100 years

Required average = $100/9$ =11$1/9$ years

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