model 4 sold & brought Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on profit & loss topic of quantitative aptitude

Questions : If I would have purchased 11 articles for Rs.10 and sold all the articles at the rate of 10 for Rs.11, the profit per cent would have been :

(a) 11%

(b) 21%

(c) 10%

(d) 100%

The correct answers to the above question in:

Answer: (b)

C.P. of an article = Rs.$10/11$

S.P. of an article = Rs.$11/10$

Profit = $11/10 - 10/11$

= ${121 - 100}/110 = Rs.21/110$

Profit % = ${{21/110} × 100}/{10/11}$

= $2100/110 × 11/10$ = 21%

Using Rule 13,
If the total cost of 'a' articles having equal cost is Rs.x
and the total selling price of 'b' articles is Rs.y,
then in the transaction gain or loss per cent is given by
$({ay - bx}/{bx})$ × 100%
Where positive value signifies 'profit'
and negative value signifies 'loss'

Here, a = 11, x = 10, b = 10, y = 11

Gain% = $({ay - bx}/{bx}) × 100%$

= $({11 × 11 - 10 × 10}/{10 × 10}) × 100%$

= $({121 - 100}/100) × 100%$ = 21%

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Read more sold brought Based Quantitative Aptitude Questions and Answers

Question : 1

A person buys some pencils at 5 for a rupee and sells them at 3 for a rupee. His gain per cent wll be :

a) 76$2/3$%

b) 56$2/3$%

c) 66$2/3$%

d) 46$2/3$%

Answer: (c)

C.P. of 5 pencils = Rs.1.

S.P. of 5 pencils = Rs.$5/3$

Gain = $5/3 - 1 = 2/3$

Gain % = ${2/3}/1 × 100 = 66{2}/3%$

Using Rule 13,

Here, a = 5, x = 1, b = 3, y = 1

Gain% = $({ay - bx}/{bx} × 100%)$

= ${5 - 3}/3 × 100% = 200/3 = 66{2}/3%$

Question : 2

100 oranges are bought for Rs.350 and sold at the rate of Rs.48 per dozen. The percentage of profit or loss is :

a) 15% gain

b) 14$2/7$% loss

c) 15% loss

d) 14$2/7$% profit

Answer: (d)

C.P. of 100 oranges = Rs.350

S.P. of 12 oranges = Rs.48

S.P. of 100 oranges

= $48/12 × 100$ = Rs.400

Profit = Rs. (400 - 350) = Rs.50

Profit % = $50/350 × 100 = 100/7 = 14{2}/7%$

Using Rule 13,

Here, a = 100, x = 350, b = 100, y = $48/12$ × 100 = 400

Gain% = $({ay - bx}/{bx})$ × 100%

= ${100 × 400 - 100 × 350}/{100 × 350}$ × 100%

= ${40 - 35}/35 × 100%$

= $100/7% = 14{2}/7$%

Question : 3

Oranges are bought at the rate of 10 for Rs.25 and sold at the rate of 9 for Rs.25. The profit percent is

a) 10%

b) 11$1/9$%

c) 9$1/11$%

d) 12$1/2$%

Answer: (b)

Suppose the number of oranges bought

= LCM of 10 and 9 = 90

C.P. of 90 oranges = $25/10 × 90$ = Rs.225

S.P. of 90 oranges = $25/9 × 90$ = Rs.250

Profit % = $25/225 × 100 = 100/9 = 11{1}/9%$

Using Rule 13,

Here, a = 10, x = 25, b = 9, y = 25

Gain% = $({ay - bx}/{bx})$ × 100%

= $({10 × 25 - 9 × 25}/{9 × 25}) × 100%$

= $({250 - 225}/{9 × 25}) × 100% = 100/9 = 11{1}/9%$

Question : 4

12 copies of a book were sold for Rs.1800/- thereby gaining costprice of 3 copies. The cost price of a copy is :

a) Rs.150/-

b) Rs.1200/-

c) Rs.120/-

d) Rs.1500/-

Answer: (c)

Let the cost price of 1 book be x

Cost price of 3 books = 3x

and, cost price of 12 books = 12x

Selling price of 12 books = 1800

= 12x + 3x = 15x

15x = 1800; x = $1800/15 = 120$

The cost price of each book = Rs.120

Question : 5

A man buys 12 articles for Rs.12 and sells them at the rate of Rs.1.25 per article. His gain percentage is :

a) 25%

b) 15%

c) 20%

d) 18%

Answer: (a)

Using Rule 1,

If S.P > C.P. then there will be profit

Profit = S.P. - C.P.

Profit% = ${\text"Profit" × 100}/{\text"C.P."}$

C.P. = 12; S.P. = 12 × 1.25 = 15

Total Profit = 15 - 12 = 3

% gain = $3/12 × 100$ = 25%

Question : 6

Oranges are bought at rate of 7 for Rs.3. At what rate per hundred must they be sold to gain 33%?

a) Rs.60

b) Rs.58

c) Rs.56

d) Rs.57

Answer: (d)

Cost price of 1 orange = Rs.$3/7$

Cost price of 100 oranges

= $3/7 × 100 = 300/7$

100% = $300/7$

133% = $300/7 × 133/100$ = Rs.57

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