model 6 sold in circular path Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (a)

Let the C.P. of A be Rs.x, then

$x × 110/100 × 120/100 = 264$

$x = {264 × 100 × 100}/{110 × 120}$ = Rs.200

Using Rule 15,

Here, $r_1 = 10%, r_2$ = 20%

C.P. for C = C.P. for A

$(1 + r_1/100)(1 + r_2/100)$

264 = C.P. for A

$(1 + 10/100)(1 + 20/100)$

C.P. for A = ${264 × 100 × 100}/{110 × 120}$ = Rs.200

Answer: (c)

Let the C.P. of A be Rs.x, then

${x × 125}/100 × 90/100$ = 675

$x = {675 × 100 × 100}/{125 × 90}$ = Rs.600

Using Rule 15,

Here, $r_1 = 25%, r_2$ = 10%, (Loss)

C.P. for C = C.P. for A

$(1 + r_1/100)(1 + r_2/100)$

675 = C.P. for A

$(1 + 25/100)(1 + 10/100)$

C.P. for A = ${675 × 100 × 100}/{125 × 90}$ = Rs.600

Answer: (a)

Let the C.P. for A be Rs.x, then

$x × 105/100 × 110/100$ = 2310

$x = {2310 × 100 × 100}/{105 × 110}$ = Rs.2000

Using Rule 15,

Here, $r_1 = 5%, r_2$ = 10%

C.P. for C = C.P. for A

$(1 + r_1/100)(1 + r_2/100)$

2310 = C.P. for A

$(1 + 5/100)(1 + 10/100)$

C.P. for A = ${2310 × 100 × 100}/{105 × 110}$ = 2000

Answer: (b)

Let the original cost of the land be Rs.x

According to the question,

345600 = P$(1+ 20/100)^3$

345600 = P$(6/5)^3 = {216P}/125$

P = ${345600 × 125}/216$ = Rs.200000

Answer: (c)

SP for Mr. X = 150000 × $105/100$ = Rs.157500

CP for Mr. Y = Rs.157500

Y sells the article to X at a loss of 2%.

SP for Mr. Y = 157500 × $98/100$ = Rs.154350

CP for Mr. X = Rs.154350

Gain of Mr. X = Rs.(157500 - 154350) = Rs.3150

Answer: (c)

Using Rule 15,

Let the C.P. of the suitcase for A be Rs.x, then

$x × 110/100 × 130/100$ = 2860

$x = {2860 × 100 × 100}/{110 × 130}$ = Rs.2000