model 6 sold in circular path Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (c)

SP for Mr. X = 150000 × $105/100$ = Rs.157500

CP for Mr. Y = Rs.157500

Y sells the article to X at a loss of 2%.

SP for Mr. Y = 157500 × $98/100$ = Rs.154350

CP for Mr. X = Rs.154350

Gain of Mr. X = Rs.(157500 - 154350) = Rs.3150

Answer: (b)

Let the original cost of the land be Rs.x

According to the question,

345600 = P$(1+ 20/100)^3$

345600 = P$(6/5)^3 = {216P}/125$

P = ${345600 × 125}/216$ = Rs.200000

Answer: (b)

Let the cost price of the bicycle for A be Rs.x

Cost price for B = selling price for A = 1.20x

Cost price for C = selling price for B = (1.25) (1.20x) = 1.5x

But 1.5x = 225 ⇒ x = $225/1.5$ = Rs.150

The cost price of the bicycle for A = Rs.150

Here, $r_1= 20%, r_2$ = 25%

C.P. for C = C.P. for A

$(1 + r_1/100)(1 + r_2/100)$

225 = C.P. for A

$(1 + 20/100)(1 + 25/100)$

C.P. for A = ${225 × 100 × 100}/{120 × 125}$ = Rs.150

Answer: (c)

Using Rule 15,

Let C.P. for A be Rs.x

$x × 120/100 × 110/100 × 225/200$ = 29.70

$x = {29.70 × 100 × 100 × 200}/{120 × 110 × 225}$ = Rs.20

Answer: (b)

Let the C.P. for A be Rs.x, then

$x × 110/100 × 105/100 = 462$

$x = {462 × 100 × 100}/{110 × 105}$ = Rs.400

Using Rule 15,

Here, $r_1 = 10%, r_2$ = 5%

C.P. for C = C.P. for A

$(1 + r_1/100)(1 + r_2/100)$

462 = C.P. for A

$(1 + 10/100)(1 + 5/100)$

C.P. for A = ${462 × 100 × 100}/{110 × 105}$ = Rs.400

Answer: (a)

Let the actual C.P. be Rs.x

$x × 125/100 × 125/100 × 125/100 = 250$

x = Rs.128