Model 8 population based Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on percentage topic of quantitative aptitude

Questions : A district has 64000 inhabitants. If the population increases at the rate of 2$1/2$% per annum, the number of inhabitants at the end of 3 years will be

(a) 69200

(b) 70000

(c) 68921

(d) 68911

The correct answers to the above question in:

Answer: (c)

Using Rule 17,

$P = P_0(1 + R/100)^T$

= $64000(1 + 5/200)^3$

= $64000(41/40)^3$

= ${64000 × 41 × 41× 41}/{40 × 40 × 40}$ = 68921

Practice percentage (Model 8 population based) Online Quiz

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Read more population based Based Quantitative Aptitude Questions and Answers

Question : 1

The value of a machine depreciates every year at the rate of 10% on its value at the beginning of that year. If the current value of the machine is Rs.729, its worth 3years ago was:

a) Rs.750.87

b) Rs.1000

c) Rs.947.10

d) Rs.800

Answer: (b)

Using Rule 18,

If the price of machine 3years ago be Rs.x. then

729 = $x(1 -10/100)^3$

729 = $x(9/100)^3$ ⇒ x = Rs.1000

Question : 2

The population of a village decreases at the rate of 20% per annum. If its population 2 years ago was 10,000, the present population is

a) 6400

b) 4600

c) 7600

d) 6000

Answer: (a)

Using Rule 17,

Present population = $10000(1 - 20/100)^2$

= $10000 × 4/5 × 4/5 = 6400$

Question : 3

In a village panchayat society 574 names are enlisted as ‘below poverty level'. If 14% of the villagers are below poverty level, the total number of villagers is

a) 4200

b) 4100

c) 4000

d) 3800

Answer: (b)

Let the total population of village be x.

According to the question,${x × 14}/100 = 574$

$x = {574 × 100}/14$ = 4100

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