Practice Population based - quantitative aptitude Online Quiz (set-1) For All Competitive Exams
Q-1) If a man receives on one-fourth of his capital 3% interest, on two third 5% and on the remainder 11%, the percentage he receives on the whole is
(a)
(b)
(c)
(d)
Required percent
= $1/4 × 3 + 2/3 × 5 + (1 - 1/4 - 2/3) × 11$
= $3/4 + 10/3 + 11/12 = {9 + 40 + 11}/12$ = 5%
Q-2) In a city, 40% of the people are illiterate and 60% are poor. Among the rich, 10% are illiterate. The percentage of the illiterate poor population is
(a)
(b)
(c)
(d)
Let the population of the city be 100.
Total illiterate people = 40
Poor people = 60; Rich people = 40
Illiterate rich people = ${40 × 10}/100$ = 4
Illiterate poor people = 40 – 4 = 36
Required percent = $36/60 × 100$ = 60%
Q-3) The population of a village was 9800. In a year, with the increase in population of males by 8% and that of females by 5%, the population of the village became 10458. What was the number of males in the village before increase ?
(a)
(b)
(c)
(d)
Let the number of males = x
Number of females= 9800 – x
According to the question,
$x × 108/100 + (9800 - x) × 105/100 = 10458$
108 x + 9800 ×105 – 105x = 1045800
3x + 1029000 = 1045800
3x = 1045800 – 1029000 = 16800
$x = 16800/3 = 5600$
Q-4) In a factory, the production of cycles rose to 48, 400 from 40,000 in 2 years. The rate of growth per annum is
(a)
(b)
(c)
(d)
Using Rule 17,
If the rate of increase per annum be R%, then
A = P$(1 + R/100)^T$
48400 = 40000$(1 + R/100)^2$
$484/400 = (1 + R/100)^2$
$121/100 = (11/10)^2 = (1 + R/100)^2$
1 + $R/100 = 11/10$
$R/100 = 11/10 - 1 = 1/10$
$R = 100/10$ = 10% per annum
Q-5) Of the 1000 inhabitants in a town 60% are males of whom 20% are literate. If of all the inhabitants, 25% are literate, then what percentage of the females of the town are ilterate ?
(a)
(b)
(c)
(d)
Population of town = 1000
Males ⇒ 600; Females ⇒ 400
Literate males = ${600 × 20}/100$ = 120
Total literate inhabitants
= ${1000 × 25}/100$ = 250
Literate females = 250 – 120 = 130
Required percent = $130/400$ × 100 = 32.5%
Q-6) The population of a town is 9000. It the number of females increases by 5% and the males by 7.5%, what will be the total population after increase. The number of females currently is 3000.
(a)
(b)
(c)
(d)
In the village,
Females = 3000; Males = 9000 – 3000 = 6000
After respective increases,
Population of village
= $3000 × 105/100 + {6000 × 107.5}/100$
= 3150 + 6450 = 9600
Q-7) In a town, the population was 8000. In one year, male population increased by 10% and female population increased by 8% but the total population increased by 9%. The number of males in the town was :
(a)
(b)
(c)
(d)
By Alligation Rule
Men : Women = 1 : 1
Number of men = $1/2 × 8000 = 4000$
Q-8) If population of women in a village is 90% of population of men, what is the population of men as a percentage of population of women ?
(a)
(b)
(c)
(d)
If the number of men be 100,then
Number of women = 90
Required per cent = $100/90 × 100 ≈ 111%$
Q-9) In a village panchayat society 574 names are enlisted as ‘below poverty level'. If 14% of the villagers are below poverty level, the total number of villagers is
(a)
(b)
(c)
(d)
Let the total population of village be x.
According to the question,${x × 14}/100 = 574$
$x = {574 × 100}/14$ = 4100
Q-10) The population of a city is 20000. It increases by 20% during the first year and 30% during the second year. The population after two years will be:
(a)
(b)
(c)
(d)
Population of city after two years
= $P(1 + R_1/100)(1 + R_2/100)$
= $20000(1 + 20/100)(1 + 30/100)$
= $20000 × 120/100 × 130/100$ = 31200