Model 8 population based Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on percentage topic of quantitative aptitude
(a) 5700
(b) 8000
(c) 6000
(d) 7500
The correct answers to the above question in:
Answer: (b)
Using Rule 17,
P = $P_0(1 + R/100)^T$
9261 = $P_0(1 + 5/100)^3$
9261 = $P_0(1 + 1/20)^3$
9261 = $P_0(21/20)^3$
$P_0 = {9261 × 20 × 20 × 20}/{21 × 21 × 21}$ = 8000
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Read more population based Based Quantitative Aptitude Questions and Answers
Question : 1
In a village panchayat society 574 names are enlisted as ‘below poverty level'. If 14% of the villagers are below poverty level, the total number of villagers is
a) 4200
b) 4100
c) 4000
d) 3800
Answer »Answer: (b)
Let the total population of village be x.
According to the question,${x × 14}/100 = 574$
$x = {574 × 100}/14$ = 4100
Question : 2
The population of a village decreases at the rate of 20% per annum. If its population 2 years ago was 10,000, the present population is
a) 6400
b) 4600
c) 7600
d) 6000
Answer »Answer: (a)
Using Rule 17,
Present population = $10000(1 - 20/100)^2$
= $10000 × 4/5 × 4/5 = 6400$
Question : 3
The value of a machine depreciates every year at the rate of 10% on its value at the beginning of that year. If the current value of the machine is Rs.729, its worth 3years ago was:
a) Rs.750.87
b) Rs.1000
c) Rs.947.10
d) Rs.800
Answer »Answer: (b)
Using Rule 18,
If the price of machine 3years ago be Rs.x. then
729 = $x(1 -10/100)^3$
729 = $x(9/100)^3$ ⇒ x = Rs.1000
Question : 4
If population of women in a village is 90% of population of men, what is the population of men as a percentage of population of women ?
a) 105%
b) 100%
c) 108%
d) 111%
Answer »Answer: (d)
If the number of men be 100,then
Number of women = 90
Required per cent = $100/90 × 100 ≈ 111%$
Question : 5
In a town, the population was 8000. In one year, male population increased by 10% and female population increased by 8% but the total population increased by 9%. The number of males in the town was :
a) 4500
b) 4000
c) 5000
d) 6000
Answer »Answer: (b)
By Alligation Rule
Men : Women = 1 : 1
Number of men = $1/2 × 8000 = 4000$
Question : 6
If the population of a town is 64000 and its annual increase is 10%, then its correct population at the end of 3 years will be :
a) 85184
b) 80000
c) 85000
d) 85100
Answer »Answer: (a)
Using Rule 17,
Population of town = $P(1 + R/100)^T$
= $64000(1 + 10/100)^3$
= $64000 × 11/10 × 11/10 × 11/10$ = 85184
GET percentage PRACTICE TEST EXERCISES
model 1 simple percentage questions
model 2 net increase or decrease in %
model 3 reducing & exceeding prices
model 4 x & y comparison
model 5 income & expenditure
model 6 consumption & remaining
model 7 marks scored in examinations
Model 8 population based
model 9 voters & election
model 10 percentage with allegations & mixture
model 11 percentage with ratios
percentage Shortcuts and Techniques with Examples
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model 1 simple percentage questions
Defination & Shortcuts … -
model 2 net increase or decrease in %
Defination & Shortcuts … -
model 3 reducing & exceeding prices
Defination & Shortcuts … -
model 4 x & y comparison
Defination & Shortcuts … -
model 5 income & expenditure
Defination & Shortcuts … -
model 6 consumption & remaining
Defination & Shortcuts … -
model 7 marks scored in examinations
Defination & Shortcuts … -
Model 8 population based
Defination & Shortcuts … -
model 9 voters & election
Defination & Shortcuts … -
model 10 percentage with allegations & mixture
Defination & Shortcuts … -
model 11 percentage with ratios
Defination & Shortcuts …
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