Model 8 population based Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on percentage topic of quantitative aptitude

Questions : If a man receives on one-fourth of his capital 3% interest, on two third 5% and on the remainder 11%, the percentage he receives on the whole is

(a) 5

(b) 4.5

(c) 5.5

(d) 5.2

The correct answers to the above question in:

Answer: (a)

Required percent

= $1/4 × 3 + 2/3 × 5 + (1 - 1/4 - 2/3) × 11$

= $3/4 + 10/3 + 11/12 = {9 + 40 + 11}/12$ = 5%

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Practice percentage (Model 8 population based) Online Quiz

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Read more population based Based Quantitative Aptitude Questions and Answers

Question : 1

In a factory, the production of cycles rose to 48, 400 from 40,000 in 2 years. The rate of growth per annum is

a) 8%

b) 9%

c) 10.5%

d) 10%

Answer: (d)

Using Rule 17,

If the rate of increase per annum be R%, then

A = P$(1 + R/100)^T$

48400 = 40000$(1 + R/100)^2$

$484/400 = (1 + R/100)^2$

$121/100 = (11/10)^2 = (1 + R/100)^2$

1 + $R/100 = 11/10$

$R/100 = 11/10 - 1 = 1/10$

$R = 100/10$ = 10% per annum

Question : 2

The population of a village increases by 5% annually. If its present population is 4410, then its population 2 years ago was

a) 4000

b) 4500

c) 3800

d) 3500

Answer: (a)

Using Rule 17,

If the population of village two years ago be $P_0$,

then P = $P_0(1 + R/100)^T$

4410 = $P_0(1 + 5/100)^2$

4410 = $P_0(1 + 1/20)^2$

4410 = $P_0(21/20)^2$

4410 = ${441P_0}/400$

$P_0 = {4410 × 400}/441$ = 4000

Question : 3

The value of a machine depreciates every year by 10%. If its present value is Rs.50,000 then the value of the machine after 2 years is _________.

a) Rs.45,000

b) Rs.40,050

c) Rs.40,005

d) Rs.40,500

Answer: (d)

Using Rule 18,

Required value = $50000(1 - 10/100)^2$

= $50000 × {9 × 9}/100$ = Rs.40500

Question : 4

In a city, 40% of the people are illiterate and 60% are poor. Among the rich, 10% are illiterate. The percentage of the illiterate poor population is

a) 60

b) 36

c) 40

d) 50

Answer: (a)

Let the population of the city be 100.

Total illiterate people = 40

Poor people = 60; Rich people = 40

Illiterate rich people = ${40 × 10}/100$ = 4

Illiterate poor people = 40 – 4 = 36

Required percent = $36/60 × 100$ = 60%

Question : 5

The population of a city is 20000. It increases by 20% during the first year and 30% during the second year. The population after two years will be:

a) 40000

b) 32000

c) 31200

d) 30000

Answer: (c)

Population of city after two years

= $P(1 + R_1/100)(1 + R_2/100)$

= $20000(1 + 20/100)(1 + 30/100)$

= $20000 × 120/100 × 130/100$ = 31200

Question : 6

Present population of a village is 67600. It has been increasing annually at the rate of 4%. What was the population of the village two years ago ?

a) 63000

b) 62500

c) 64756

d) 65200

Answer: (b)

Using Rule 17,

Population of the village two years ago

= $P/(1 + R/100)^2 = 67600/(1 + 4/100)^2$

= ${67600 × 25 × 25}/{26 × 26}$ = 62500

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GET percentage PRACTICE TEST EXERCISES

model 1 simple percentage questions

model 2 net increase or decrease in %

model 3 reducing & exceeding prices

model 4 x & y comparison

model 5 income & expenditure

model 6 consumption & remaining

model 7 marks scored in examinations

Model 8 population based

model 9 voters & election

model 10 percentage with allegations & mixture

model 11 percentage with ratios
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