Model 8 population based Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on percentage topic of quantitative aptitude

Questions : A man received Rs.8,80,000 as his annual salary of the year 2007 which was 10% more than his annual salary in 2006. His annual salary in the year 2006 was

(a) Rs.8,00,000

(b) Rs.4,80,000

(c) Rs.4,00,000

(d) Rs.8,40,000

The correct answers to the above question in:

Answer: (a)

Using Rule 17,

Let the man's annual salary in 2006 be Rs.x.

${110x}/100$ = 880000

$x = {880000 × 100}/110$ = Rs.800000

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Read more population based Based Quantitative Aptitude Questions and Answers

Question : 1

Present population of a village is 67600. It has been increasing annually at the rate of 4%. What was the population of the village two years ago ?

a) 63000

b) 62500

c) 64756

d) 65200

Answer: (b)

Using Rule 17,

Population of the village two years ago

= $P/(1 + R/100)^2 = 67600/(1 + 4/100)^2$

= ${67600 × 25 × 25}/{26 × 26}$ = 62500

Question : 2

The population of a city is 20000. It increases by 20% during the first year and 30% during the second year. The population after two years will be:

a) 40000

b) 32000

c) 31200

d) 30000

Answer: (c)

Population of city after two years

= $P(1 + R_1/100)(1 + R_2/100)$

= $20000(1 + 20/100)(1 + 30/100)$

= $20000 × 120/100 × 130/100$ = 31200

Question : 3

In a city, 40% of the people are illiterate and 60% are poor. Among the rich, 10% are illiterate. The percentage of the illiterate poor population is

a) 60

b) 36

c) 40

d) 50

Answer: (a)

Let the population of the city be 100.

Total illiterate people = 40

Poor people = 60; Rich people = 40

Illiterate rich people = ${40 × 10}/100$ = 4

Illiterate poor people = 40 – 4 = 36

Required percent = $36/60 × 100$ = 60%

Question : 4

The value of a property decreases every year at the rate of 5%. If its present value is Rs.4,11,540, what was its value 3 years ago ?

a) Rs.4,60,000

b) Rs.4,50,000

c) Rs.4,75,000

d) Rs.4,80,000

Answer: (d)

Using Rule 18,

Value of the property 3 years ago

= $P/{(1 - R/100)^T} = 411540/{(1 - 5/100)^3}$

= ${411540 × 20 × 20 × 20}/{19 × 19 × 19}$ = Rs.480000

Question : 5

The value of a machine is Rs.6,250. It decreases by 10% during the first year, 20% during the second year and 30% during the third year. What will be the value of the machine after 3 years?

a) Rs.3,050

b) Rs.2,650

c) Rs.3,150

d) Rs.3,510

Answer: (c)

Using Rule 28,

Population after ‘n' years = $P(1 ± R_1/100)(1 ± R_2/100)…(1 ± R_n/100)$

Required price of the machine

= $6250(1 - 10/100)(1 - 20/100)(1 - 30/100)$

= $6250 × 90/100 × 80/100 × 70/100$ = Rs.3150

Question : 6

The population of a town 2 years ago was 62,500. Due to migration to big cities, it decreases every year at the rate of 4%. The present population of the town is:

a) 56,700

b) 57,600

c) 76,000

d) 75,000

Answer: (b)

Using Rule 18,

Let the present population be P.

P = $62500(1 - 4/100)^2$

= $62500 × 24/25 × 24/25$ = 57600

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GET percentage PRACTICE TEST EXERCISES

model 1 simple percentage questions

model 2 net increase or decrease in %

model 3 reducing & exceeding prices

model 4 x & y comparison

model 5 income & expenditure

model 6 consumption & remaining

model 7 marks scored in examinations

Model 8 population based

model 9 voters & election

model 10 percentage with allegations & mixture

model 11 percentage with ratios
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