model 7 marks scored in examinations Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on percentage topic of quantitative aptitude

Questions : In an examination 60% of the students pass in English, 70% pass in Hindi and 40% pass in both. What percent of students fail in both English and Hindi?

(a) 25%

(b) 20%

(c) 30%

(d) 10%

The correct answers to the above question in:

Answer: (d)

The percentage of students who pass in one or two or both subjects

= 60 + 70 – 40 = 90

Percentage of failed students = 100 – 90 = 10%

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Read more marks and examinations Based Quantitative Aptitude Questions and Answers

Question : 1

A student has to secure minimum 35% marks to pass in an examination. If he gets 200 marks and fails by 10 marks, then the maximum marks are

a) 500

b) 400

c) 600

d) 300

Answer: (c)

Let the maximum marks be x.

According to the question,

35% of x = 200 +10 ⇒ ${35x}/100 = 210$

x = ${210 × 100}/35 = 600$

Using Rule 24,

a = 35%, b = 200, c = 10

Maximum Marks = ${100 × (b + c)}/a$

= ${100(200 + 10)}/35$ = 600 Marks

Question : 2

A candidate who scores 30 per cent fails by 5 marks, while another candidate who scores 40 per cent marks gets 10 more than minimum pass marks. The minimum marks required to pass are

a) 100

b) 70

c) 150

d) 50

Answer: (d)

Let the full marks in that examination were x.

According to the question,

${30x}/100 + 5 = {40x}/100 - 10$

${4x}/10 - {3x}/10 = 10 + 5$

$x/10 = 15$ ∴ x = 150

Minimum pass marks

$30/100 × 150 + 5 = 50$

Using Rule 22,

m = 30%, n = 40%, p = 5, q = 10.

Maximum marks = $100/{(n - m)} × (p + q)$

= $100/{(40 - 30)} × (5 + 10) = 150$

Minimum passing marks = $150 × 30/100 + 5$

= 45 + 5 = 50

Question : 3

In an examination there were 640 boys and 360 girls. 60% of boys and 80% of girls were successful. The percentage of failure was :

a) 30.5%

b) 60%

c) 32.8%

d) 20%

Answer: (c)

Total number of students = 640 + 360 = 1000

Number of successful boys = 60% of 640 = 384

Number of successful girls = 80% of 360 = 288

Total number of successful students = 384 + 288 = 672

Number of unsuccessful students = 1000 – 672 = 328

Required percentage = ${328 × 100}/1000 = 32.8%$

Using Rule 25,

B = 640, G = 360, b = 60%, g = 80%

Percentage of passed students = $({Bb + Gg}/{B + G})%$

= ${640 × 60 + 360 × 80}/{640 + 360}$

= ${38400 + 28800}/1000 = 67200/1000 = 67.2%$

% of failed students = 100 – 67.2% = 32.8%

Question : 4

In two successive years 100 and 75 students of a school appeared at the final examination. Respectively, 75% and 60% of them passed. The average rate of pass is

a) 80$1/2$%

b) 78%

c) 80%

d) 68$4/7$%

Answer: (d)

Number of students passed in first year = 75

Number of students passed in second year

= ${60 × 75}/100 = 45$

Total number of passed students = 75+45=120

Total number of appeared students =175

∴ Required percentage

= $120/175 × 100 = 68{4}/7%$

Question : 5

In an examination, 1100 boys and 900 girls appeared. 50% of the boys and 40% of the girls passed the examination. The percentage of candidates who failed

a) 50%

b) 45.5%

c) 54·5%

d) 45%

Answer: (c)

Failed candidates = ${1100 × 50}/100 + {900 × 60}/100$

= 550 + 540 = 1090

Required percentage = $1090/2000 × 100 = 54.5%$

Using Rule 25,

B = 1100, b = 50%, G = 900, g = 40%

Percentage of failed candidates = ${(Bb + Gg)}/{B + G}%$

= ${1100 × 50 + 900 × 40}/{1100 + 900}$

= ${55000 + 36000}/2000$

= $91/2$ = 45.5%

Question : 6

In an examination a candidate must secure 40% marks to pass. A candidate, who gets 220 marks, fails by 20 marks. What are the maximum marks for the examination?

a) 600

b) 800

c) 450

d) 1200

Answer: (a)

According to question,

40% ⇒ 220 + 20 or 40% ⇒ 240

100% ⇒ $240/40 × 100 = 600$

Using Rule 24,

a = 40%, b = 220, c = 20

Total Marks = ${100(220 +20)}/40$

=${100 × 240}/40 = 600$

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