model 7 marks scored in examinations Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (d)

Number of students passed in first year = 75

Number of students passed in second year

= ${60 × 75}/100 = 45$

Total number of passed students = 75+45=120

Total number of appeared students =175

∴ Required percentage

= $120/175 × 100 = 68{4}/7%$

Answer: (d)

The percentage of students who pass in one or two or both subjects

= 60 + 70 – 40 = 90

Percentage of failed students = 100 – 90 = 10%

Answer: (c)

Let the maximum marks be x.

According to the question,

35% of x = 200 +10 ⇒ ${35x}/100 = 210$

x = ${210 × 100}/35 = 600$

Using Rule 24,

a = 35%, b = 200, c = 10

Maximum Marks = ${100 × (b + c)}/a$

= ${100(200 + 10)}/35$ = 600 Marks

Answer: (a)

According to question,

40% ⇒ 220 + 20 or 40% ⇒ 240

100% ⇒ $240/40 × 100 = 600$

Using Rule 24,

a = 40%, b = 220, c = 20

Total Marks = ${100(220 +20)}/40$

=${100 × 240}/40 = 600$

Answer: (a)

Let total number of students = 100

Number of failures in Maths = 34

Number of failures in English = 42

Number of failures in both subjects = 20

Number of failures in Maths or English or both

= 34 + 42 – 20 = 56

Number of students who passed in both subjects

= 100 – 56 = 44

The required percentage = 44%

Using Rule 23,

a = 34%, b = 42%, c = 20%

Passed candidates in both the subjects

= 100 – (a + b – c)

= 100 – (34 + 42 – 20) = 100 – 56 = 44%

Answer: (d)

Let marks obtained by Supriyo = x

${9x}/10 = 81 ⇒ x = {81 × 10}/9 = 90$