model 5 income & expenditure Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on percentage topic of quantitative aptitude

Questions : If the total monthly income of 16 persons is Rs.80,800 and the income of one of them is 120% of the average income, then his income is

(a) Rs.6,160

(b) Rs.6,060

(c) Rs.5,050

(d) Rs.6,600

The correct answers to the above question in:

Answer: (b)

Let the required income be Rs.x Average monthly income

= Rs.$(80800/16)$ = Rs.5050

x = 120% of 5050

= Rs.$(120/100 × 5050)$ = Rs.6060

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Read more income expenditure Based Quantitative Aptitude Questions and Answers

Question : 1

A man spends 75% of his income. His income increased by 20% and he increased his expenditure by 15%. His savings will then be increased by

a) 35%

b) 33$1/3$%

c) 33%

d) 40%

Answer: (a)

Let man's income = Rs.100

Savings = 100 – 75 = Rs.25

New income = Rs.120

Savings = $120 - {75 × 115}/100 = 120 - 345/4$

= ${480 – 345}/4 = Rs.135/4$

Increase in savings =$135/4 - 25 = Rs.35/4$

Percentage increase = ${35/4}/25 × 100 = 35%$

Question : 2

A person who spends 66$2/3$% of his income is able to save Rs.1,200 per month. His monthly expenses (in Rs.) is :

a) 3,000

b) 2,400

c) 1,200

d) 3,200

Answer: (b)

Savings = 100% - 66$2/3$%

= 33$1/3$% Since, 33$1/3$% ≡ Rs.1200

100% ≡ $1200/100 ×3 × 100$ = Rs.3600

Expenses = 3600 - 1200 = Rs.2400

Aliter : Using Rule 20,

{If a person saves ‘R' rupees after spending x% on food, y% on cloth and z% on entertainment of his income then,

Monthly income = $100/{100 - (x + y +z)}× R$}

Here, R = Rs.1200; x = 66$2/3$%

Monthly income = $100/{100 - 66{2}/3} × 1200$

= $100/{100 - 200/3} × 1200$

= $300/100 × 1200$ = Rs.3600

Expenses = Income – savings = 3600 – 1200 = 2400

Question : 3

If A's income is 40% less than that of B, how much percent B's income is more than that of A?

a) 66.66%

b) 40%

c) 60%

d) 33.33%

Answer: (a)

Using Rule 9,

If ‘x' is A% less than ‘y', then y is more than ‘x' by

Required% = $(A/(100 - A)× 100)%$(increase)

Required percentage = $x/{100 - x} × 100$

= $40/60 × 100 = 200/3$= 66.66%

Question : 4

X's income is 20% more than that of Y. What per cent is Y's income less than X ?

a) 83$2/3$%

b) 16$2/3$%

c) 83$1/3$%

d) 16$1/3$%

Answer: (b)

Using Rule 8,

Required percentage = $20/{100 + 20} × 100$

= $50/3 =16{2}/3%$

Question : 5

Radha spends 40% of her salary on food, 20% on house rent, 10% on entertainment and 10% on conveyance. If her savings at the end of a month are Rs.1500, then her salary per month (in Rs.) is

a) Rs.6000

b) Rs.7500

c) Rs.8000

d) Rs.10000

Answer: (b)

Radha's total percentage expenditure

= (40 + 20 + 10 + 10)% = 80%

Percentage savings =100 – 80 = 20%

Now, 20% of her total salary = 1500

Her total salary = ${1500 ×100}/20$ = Rs.7500

Using Rule 20,

Here, Monthly income = $100/{100 - (40 + 20 +10 +10)} ×1500$

= $150000/{100 – 80} = 150000/20$ =Rs.7500

Question : 6

What per cent decrease in salaries would exactly cancel out the 20 per cent increase?

a) 33$1/3$%

b) 16$2/3$%

c) 20%

d) 18%

Answer: (b)

Using Rule 8,

If the income of a man is A% more than another man, then income of another man is less in comparison to the 1st man by

$(A/(100 + A)× 100)%$

Simple method

Required answer = $(20/{100 + 20} × 100)$%

= $(20/120 × 100)% = 50/3% = 16{2}/3%$

Need More Mcqs on percentage of model 5 income & expenditure Click Here »
GET percentage PRACTICE TEST EXERCISES

model 1 simple percentage questions

model 2 net increase or decrease in %

model 3 reducing & exceeding prices

model 4 x & y comparison

model 5 income & expenditure

model 6 consumption & remaining

model 7 marks scored in examinations

Model 8 population based

model 9 voters & election

model 10 percentage with allegations & mixture

model 11 percentage with ratios
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