model 2 gain lost percentage Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (c)

Let CP of each coconut be Rs.1.

CP of 2500 coconuts = Rs.2500

SP of 2500 coconuts = Rs.2750

Gain % = ${2750 - 2500}/2500 × 100$ = 10%

Using Rule 8,

Here, x = 2750, y = 2500

Gain % = $({x - y}/y) × 100$

= $({2750 - 2500}/2500) × 100$

= $250/2500 × 100$ = 10%

Answer: (a)

Required profit per cent =${10 - 9}/9 × 100$

= $1/9 × 100 = 11{1}/ 9%$

Using Rule 8,

Here, x = 10, y = 9

Profit % = $({x - y}/y) × 100$

= $({10 - 9}/9) × 100$

= $1/9 × 100 = 11{1}/9%$

Answer: (b)

If the CP of A articles be equal to SP of B articles, then

Loss percent = ${B - A}/B × 100$

= ${16 - 10}/16 × 100 = 6/16 × 100$ = 37.5%

Using Rule 8,

Here, x = 10, y = 16

Loss % = $({y - x}/y) × 100$

= $({16 - 10}/16) × 100 = 600/16$ = 37.5%

Answer: (c)

Let C.P. be Rs.1

C.P. of 3 articles = Rs.3 = S.P. of P. of 5 articles.

Loss% = $({5 - 3})/5 × 100$ = 2 × 20 = 40%

Using Rule 8,

Here, x = 3, y = 5

Loss % = $({x - y}/y) × 100$

$({3 - 5}/5) × 100$ = - 40%

(–ve sign shows loss)

= 40 %

Answer: (a)

Let the C.P. of each article be Rs.1.

C.P. of 10 articles = Rs.10

and S.P. of 10 articles = Rs.11

Profit percent = ${11 - 10}/10 × 100$ = 10%

Using Rule 8,

Here, x = 11, y = 10

Profit % = $({x - y}/y) × 100$

= ${11 - 10}/10 × 100 = 100/10$ = 10%

Answer: (c)

Let the CP of 1 apple = Rs.1

CP of 18 apples = Rs.18

SP of 18 apples = Rs.24

Gain percent = $6/18 × 100 = 100/3 = 33{1}/3%$

Using Rule 8,

Here, x = 24, y = 18

Gain % = $({x - y}/y) × 100$

= ${24 - 18}/18 × 100 = 6/18 × 100 = 33{1}/3%$