model 2 gain lost percentage Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on profit & loss topic of quantitative aptitude

Questions : The cost price of 25 articles is equal to the selling price of 20 of them. The gain or loss percent is given by

(a) 20% loss

(b) 25% gain

(c) 75% gain

(d) 60% loss

The correct answers to the above question in:

Answer: (b)

Percentage profit = ${25 - 20}/20 × 100$ = 25%

Using Rule 8,

Here, x = 25, y = 20

Gain % = $({x - y}/y) × 100$

= ${25 - 20}/20 × 100 = 500/20$ = 25%

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Read more gain lost percentage Based Quantitative Aptitude Questions and Answers

Question : 1

The cost price of 40 articles is the same as the selling price of 25 articles. Find the gain per cent.

a) 65%

b) 60%

c) 75%

d) 15%

Answer: (b)

Gain per cent

= ${40 - 25}/25 × 100 = 15/25 × 100 = 60%$

Using Rule 8,

Here, x = 40, y = 25

Gain % = $({x - y}/y) × 100$

= ${40 - 25}/25 × 100 = 15/25 × 100$ = 60%

Question : 2

If the cost price of 18 articles is equal to the selling price of 16 articles, the gain or loss is

a) 25% gain

b) 25% loss

c) 12$1/2$% gain

d) 12$1/2$% loss

Answer: (c)

Percentage profit = ${18 - 16}/16 × 100$

= $25/2 = 12{1}/2$%

Using Rule 8,

Here, x = 18, y = 16

Gain % = $({x - y}/y) × 100$

= ${18 - 16}/16 × 100$

= $2/16 × 100 = 25/2 = 12{1}/2$%

Question : 3

The cost price of 36 books is equal to the selling price of 30 books. The gain per cent is :

a) 20%

b) 16$4/6$%

c) 82$2/6$%

d) 18%

Answer: (a)

Using Rule 8,

If cost price of 'x' articles is equal to selling price of 'y' articles,
then Selling Price = x, Cost Price = y
Hence, Profit or Loss% = ${x - y}/y × 100$

Required profit = ${36 - 30}/30 × 100$ = 20%

Question : 4

The cost price of 8 articles is equal to the selling price of 9 articles. The profit or loss per cent in the transaction is

a) 12$1/2$% loss

b) 12$1/2$% profit

c) 11$1/9$% profit

d) 11$1/9$% loss

Answer: (d)

Let the CP of each article be Rs.1

CP of 9 articles = Rs.9

SP of 9 articles = Rs.8

Loss = Rs.1; Loss % = $1/9$ × 100

Loss % = $100/9 = 11{1}/9%$

Using Rule 8,

Here, x = 8, y = 9

Loss % = $({y - x}/y) × 100$

= $({9 - 8}/9) × 100 = 100/9 = 11{1}/9%$

Question : 5

The cost price of a book is Rs.150. At what price should it be sold to gain 20% ?

a) Rs.120

b) Rs.180

c) Rs.80

d) Rs.100

Answer: (b)

S.P. of book = ${150 × 120}/100$ = Rs.180

Using Rule 3,
If an object is sold on r% Profit.

then,S.P. = C.P$[{100 + \text"Profit%"}/100]$
or
C.P. = S.P$[100/{100 + \text"Profit%"}]$

Similarly, If an object is sold on r% loss, then

S.P. = C.P.$[{100 - \text"Loss%"}/100]$
or
C.P. = S.P$[100/{100 - \text"Loss%"}]$

S.P. = C.P.$({100 + \text"Profit%"}/100)$

= ${150 × (100 + 20)}/100$

= ${150 × 120}/100$ = Rs.180

Question : 6

The selling price of 10 oranges is the cost price of 13 oranges. Then the profit percentage is

a) 30%

b) 10%

c) 3%

d) 13%

Answer: (a)

Let the CP of 1 orange = Rs.1

SP of 10 oranges = Rs.13

Gain percent = ${13 - 10}/10 × 100$ = 30%

Using Rule 8,

Here, x = 13, y = 10

Profit % = $({x - y}/y) × 100$

= $({13 - 10}/10) × 100 = 300/10$ = 30%

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GET profit & loss PRACTICE TEST EXERCISES

Model 1 Basic Concepts of C.P and S.P

model 2 gain lost percentage

model 3 gain/loss % with C.P/S.P

model 4 sold & brought

model 5 marked price

model 6 sold in circular path

model 7 sold at loss

model 8 two article sold in different rates

model 9 selling an article & interchanging its values

model 10 reduced/increased price of an article

model 11 ratio & partnership
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