model 2 gain lost percentage Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on profit & loss topic of quantitative aptitude

Questions : Mahesh purchased a radio at $9/10$ of its selling price and sold it at 8% more than its original selling price. His gain per cent is :

(a) 20 %

(b) 18%

(c) 8 %

(d) 10 %

The correct answers to the above question in:

Answer: (a)

Using Rule 1,

If S.P > C.P. then there will be profit

Profit = S.P. - C.P.

Profit% = ${\text"Profit" × 100}/{\text"C.P."}$

Let the original selling price of radio = Rs.100

C.P. of radio = Rs.90

New selling price = Rs.108

Gain per cent = $18/90 × 100$ = 20%

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Read more gain lost percentage Based Quantitative Aptitude Questions and Answers

Question : 1

The selling price of 10 oranges is the cost price of 13 oranges. Then the profit percentage is

a) 30%

b) 10%

c) 3%

d) 13%

Answer: (a)

Let the CP of 1 orange = Rs.1

SP of 10 oranges = Rs.13

Gain percent = ${13 - 10}/10 × 100$ = 30%

Using Rule 8,

Here, x = 13, y = 10

Profit % = $({x - y}/y) × 100$

= $({13 - 10}/10) × 100 = 300/10$ = 30%

Question : 2

The cost price of a book is Rs.150. At what price should it be sold to gain 20% ?

a) Rs.120

b) Rs.180

c) Rs.80

d) Rs.100

Answer: (b)

S.P. of book = ${150 × 120}/100$ = Rs.180

Using Rule 3,
If an object is sold on r% Profit.

then,S.P. = C.P$[{100 + \text"Profit%"}/100]$
or
C.P. = S.P$[100/{100 + \text"Profit%"}]$

Similarly, If an object is sold on r% loss, then

S.P. = C.P.$[{100 - \text"Loss%"}/100]$
or
C.P. = S.P$[100/{100 - \text"Loss%"}]$

S.P. = C.P.$({100 + \text"Profit%"}/100)$

= ${150 × (100 + 20)}/100$

= ${150 × 120}/100$ = Rs.180

Question : 3

The cost price of 8 articles is equal to the selling price of 9 articles. The profit or loss per cent in the transaction is

a) 12$1/2$% loss

b) 12$1/2$% profit

c) 11$1/9$% profit

d) 11$1/9$% loss

Answer: (d)

Let the CP of each article be Rs.1

CP of 9 articles = Rs.9

SP of 9 articles = Rs.8

Loss = Rs.1; Loss % = $1/9$ × 100

Loss % = $100/9 = 11{1}/9%$

Using Rule 8,

Here, x = 8, y = 9

Loss % = $({y - x}/y) × 100$

= $({9 - 8}/9) × 100 = 100/9 = 11{1}/9%$

Question : 4

If the cost price of 12 oranges is equal to selling price of 10 oranges, then the percentage of profit is

a) 16$2/3$%

b) 20%

c) 25%

d) 18%

Answer: (b)

Let C.P. of each orange be Rs.1

Then, C.P. of 10 oranges = Rs.10

S.P. of 10 oranges = Rs.12

Gain % = $(2/10 × 100)$% = 20%

Using Rule 8,

Here, x = 12, y = 10

Profit % = $({x - y}/y) × 100$

= $({12 - 10}/10) × 100$ = 20%

Question : 5

If the cost price of 10 articles is equal to the selling price of 7 articles, then the gain or loss per cent is :

a) 51% gain

b) 42$6/7$% gain

c) 42$6/7$% loss

d) 35 % loss

Answer: (b)

Let C.P. of each article be Rs. 1

Then, C.P. of 7 articles = Rs. 7

S.P. of 7 articles = Rs. 10

Gain % = ${10 - 7}/7 × 100 = 300/7 = 42{6}/7%$

Using Rule 8,

Here, x = 10, y = 7

Profit % = $({x - y}/y) × 100$

= $({10 - 7}/7) × 100 = 300/7 = 42{6}/7%$

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