model 3 gain/loss % with C.P/S.P Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on profit & loss topic of quantitative aptitude

Questions : Loss of 20% on selling price is equal to x% loss on cost price. What is the value of x ?

(a) 16$2/3$

(b) 20

(c) 16

(d) 20

The correct answers to the above question in:

Answer: (a)

$20/100 = 1/5 = \text"C.P.- S.P."/\text"S.P."$

$5x_1 - 5y = y$

Where C.P. = Rs.$x_1$; S.P. = Rs.y

$5x_1$ = 6y ⇒ y = Rs.$5/6x_1$

$x = {x_1 - {5/6}x_1}/{x_1} × 100$

= $x_1/{6x_1} × 100 = 50/3 = 16{2}/3%$

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Read more gain loss with cp sp Based Quantitative Aptitude Questions and Answers

Question : 1

If the profit per cent got on selling an article is numerically equal to its cost price in rupees and the selling price is 39, then cost price (in ) will be

a) 28

b) 22

c) 30

d) 20

Answer: (c)

Using Rule 3,
If an object is sold on r% Profit.

then,S.P. = C.P$[{100 + \text"Profit%"}/100]$
or
C.P. = S.P$[100/{100 + \text"Profit%"}]$

Similarly, If an object is sold on r% loss, then

S.P. = C.P.$[{100 - \text"Loss%"}/100]$
or
C.P. = S.P$[100/{100 - \text"Loss%"}]$

Let the CP of the article be x Gain % = x%

${39 - x}/x × 100$

$3900 - 100x = x^2$

$x^2 + 100x - 3900$ = 0

$x^2 + 130x - 30x - 3900$ = 0

x (x + 130) - 30 (x + 130) = 0

(x - 30) (x + 130) = 0

x = 30 as x cannot be negative

Question : 2

If the profit on selling an article for 425 is the same as the loss on selling it for 355, then the cost price of the article is

a) 390

b) 380

c) 400

d) 370

Answer: (a)

Let the C.P. of article be x,

then, 425 - x = x - 355

2x = 425 + 355 = 780

x = $780/2$ = Rs.390

Question : 3

If the cost price of 28 articles is equal to the sale price of 21 articles, then the percentage of profit is :

a) 20%

b) 33$1/3$%

c) 22%

d) 12%

Answer: (b)

Let the C.P. of each article be Re. 1.

C.P. of 21 articles = Rs. 21

S.P. of 21 articles = Rs. 28

∴ Profit per cent = ${28 - 21}/21 × 100$

= $100/3 = 33{1}/3%$

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