model 3 gain/loss % with C.P/S.P Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on profit & loss topic of quantitative aptitude

Questions : If the profit per cent got on selling an article is numerically equal to its cost price in rupees and the selling price is 39, then cost price (in ) will be

(a) 28

(b) 22

(c) 30

(d) 20

The correct answers to the above question in:

Answer: (c)

Using Rule 3,
If an object is sold on r% Profit.

then,S.P. = C.P$[{100 + \text"Profit%"}/100]$
or
C.P. = S.P$[100/{100 + \text"Profit%"}]$

Similarly, If an object is sold on r% loss, then

S.P. = C.P.$[{100 - \text"Loss%"}/100]$
or
C.P. = S.P$[100/{100 - \text"Loss%"}]$

Let the CP of the article be x Gain % = x%

${39 - x}/x × 100$

$3900 - 100x = x^2$

$x^2 + 100x - 3900$ = 0

$x^2 + 130x - 30x - 3900$ = 0

x (x + 130) - 30 (x + 130) = 0

(x - 30) (x + 130) = 0

x = 30 as x cannot be negative

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Read more gain loss with cp sp Based Quantitative Aptitude Questions and Answers

Question : 1

Loss of 20% on selling price is equal to x% loss on cost price. What is the value of x ?

a) 16$2/3$

b) 20

c) 16

d) 20

Answer: (a)

$20/100 = 1/5 = \text"C.P.- S.P."/\text"S.P."$

$5x_1 - 5y = y$

Where C.P. = Rs.$x_1$; S.P. = Rs.y

$5x_1$ = 6y ⇒ y = Rs.$5/6x_1$

$x = {x_1 - {5/6}x_1}/{x_1} × 100$

= $x_1/{6x_1} × 100 = 50/3 = 16{2}/3%$

Question : 2

If the profit on selling an article for 425 is the same as the loss on selling it for 355, then the cost price of the article is

a) 390

b) 380

c) 400

d) 370

Answer: (a)

Let the C.P. of article be x,

then, 425 - x = x - 355

2x = 425 + 355 = 780

x = $780/2$ = Rs.390

Question : 3

If the cost price of 28 articles is equal to the sale price of 21 articles, then the percentage of profit is :

a) 20%

b) 33$1/3$%

c) 22%

d) 12%

Answer: (b)

Let the C.P. of each article be Re. 1.

C.P. of 21 articles = Rs. 21

S.P. of 21 articles = Rs. 28

∴ Profit per cent = ${28 - 21}/21 × 100$

= $100/3 = 33{1}/3%$

Question : 4

A vendor loses the selling price of 4 oranges on selling 36 oranges. His loss per cent is

a) 10%

b) 9%

c) 11$1/2$%

d) 12$1/2$%

Answer: (a)

S.P. of 36 oranges

= C.P. of 36 oranges - S.P. of 4 oranges

S.P. of 40 oranges = C.P. of 36 oranges

Loss per cent = $4/40 × 100 = 10%$

Using Rule 9,

Here, x = 36, y = 4

Here, loss % = ${y × 100}/{x + y}$

= ${4 × 100}/{36 + 4}$ = 10%

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GET profit & loss PRACTICE TEST EXERCISES

Model 1 Basic Concepts of C.P and S.P

model 2 gain lost percentage

model 3 gain/loss % with C.P/S.P

model 4 sold & brought

model 5 marked price

model 6 sold in circular path

model 7 sold at loss

model 8 two article sold in different rates

model 9 selling an article & interchanging its values

model 10 reduced/increased price of an article

model 11 ratio & partnership
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