model 3 gain/loss % with C.P/S.P Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (a)

S.P. of 36 oranges

= C.P. of 36 oranges - S.P. of 4 oranges

S.P. of 40 oranges = C.P. of 36 oranges

Loss per cent = $4/40 × 100 = 10%$

Using Rule 9,

Here, x = 36, y = 4

Here, loss % = ${y × 100}/{x + y}$

= ${4 × 100}/{36 + 4}$ = 10%

Answer: (b)

Let the C.P. of each article be Re. 1.

C.P. of 21 articles = Rs. 21

S.P. of 21 articles = Rs. 28

∴ Profit per cent = ${28 - 21}/21 × 100$

= $100/3 = 33{1}/3%$

Answer: (a)

Let the C.P. of article be x,

then, 425 - x = x - 355

2x = 425 + 355 = 780

x = $780/2$ = Rs.390

Answer: (a)

S.P. of 3 articles

= C.P. of 21 articles - S.P. of 21 articles

S.P. of 24 articles = C.P. of 21 articles

Loss percent = ${24 - 21}/24 × 100 = 12{1}/2%$

Using Rule 9,

Here, x = 21, y = 3

∴ Loss% = ${y × 100}/{x + y}$

= ${3 × 100}/{21 + 3} = 100/8$

= $25/2 = 12{1}/2%$

Answer: (d)

SP of 12 ball pens = CP of 12 ball pens + SP of 4 ball pens.

SP of 8 ball pens = CP of 12 ball pens

Gain per cent = $4/8 × 100 = 50%$

Using Rule 9,

Here, x = 12, y = 4

∴ Profit% = ${y × 100}/{x - y}$

= ${4 × 100}/{12 - 4}$ = 50%

Answer: (b)

Let the cost price be x.

(100 + x)% of x = 144

(100 + x)x = 14400

$x^2 + 100x - 14400$ = 0

$x^2 + 180x - 80x - 14400$ = 0

x(x + 180) - 80 (x + 180) = 0

(x + 180) (x - 80) = 0

x = Rs.80 [x ≠180]