model 3 gain/loss % with C.P/S.P Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (a)

S.P. of 3 articles

= C.P. of 21 articles - S.P. of 21 articles

S.P. of 24 articles = C.P. of 21 articles

Loss percent = ${24 - 21}/24 × 100 = 12{1}/2%$

Using Rule 9,

Here, x = 21, y = 3

∴ Loss% = ${y × 100}/{x + y}$

= ${3 × 100}/{21 + 3} = 100/8$

= $25/2 = 12{1}/2%$

Answer: (d)

CP of 144 hens - SP of 144 hens = Loss = SP of 6 hens

SP of 150 hens = CP of 144 hens

Let CP of each hen = Rs.1

CP of 150 hens = Rs.150

SP of 150 hens = Rs.144

Loss% = $6/150$ × 100 = 4%

Here, x = 144, y = 6

∴ Loss% = ${y × 100}/{x + y}$

= $600/{144 + 6}$

= $600/150$ = 4%

Answer: (a)

S.P. of 36 oranges

= C.P. of 36 oranges - S.P. of 4 oranges

S.P. of 40 oranges = C.P. of 36 oranges

Loss per cent = $4/40 × 100 = 10%$

Using Rule 9,

Here, x = 36, y = 4

Here, loss % = ${y × 100}/{x + y}$

= ${4 × 100}/{36 + 4}$ = 10%

Answer: (b)

Let the cost price be x.

(100 + x)% of x = 144

(100 + x)x = 14400

$x^2 + 100x - 14400$ = 0

$x^2 + 180x - 80x - 14400$ = 0

x(x + 180) - 80 (x + 180) = 0

(x + 180) (x - 80) = 0

x = Rs.80 [x ≠180]

Answer: (b)

Let the C.P. of article be Rs.100 and its S.P. be Rs.x.

According to the question.

When S.P. = Rs.$x/2$

Loss per cent = ${100 - x/2}/100 × 100$

$100 - x/2 = 51/2$

$x/2 = 100 - 51/2 = {200 - 51}/2$

x = Rs.149

Required profit percent = 49%

Answer: (c)

Let C.P. of a ball = x

S.P. of 17 balls = Rs.720

17x - 720 = 5x

12x = 720 ⇒ x = Rs.60