model 3 gain/loss % with C.P/S.P Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on profit & loss topic of quantitative aptitude

Questions : By selling 1 dozen ball pens, a shopkeeper earned the profit equal to the selling price of 4 ball pens. His profit per cent is

(a) 33$1/3$%

(b) 40%

(c) 31$1/4$%

(d) 50%

The correct answers to the above question in:

Answer: (d)

SP of 12 ball pens = CP of 12 ball pens + SP of 4 ball pens.

SP of 8 ball pens = CP of 12 ball pens

Gain per cent = $4/8 × 100 = 50%$

Using Rule 9,

Here, x = 12, y = 4

∴ Profit% = ${y × 100}/{x - y}$

= ${4 × 100}/{12 - 4}$ = 50%

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Read more gain loss with cp sp Based Quantitative Aptitude Questions and Answers

Question : 1

The loss incurred on selling 21 articles equals the selling price of 3 articles. Then the loss per cent is

a) 12$1/2$%

b) 10%

c) 11$1/9$%

d) 9$1/11$%

Answer: (a)

S.P. of 3 articles

= C.P. of 21 articles - S.P. of 21 articles

S.P. of 24 articles = C.P. of 21 articles

Loss percent = ${24 - 21}/24 × 100 = 12{1}/2%$

Using Rule 9,

Here, x = 21, y = 3

∴ Loss% = ${y × 100}/{x + y}$

= ${3 × 100}/{21 + 3} = 100/8$

= $25/2 = 12{1}/2%$

Question : 2

By selling 144 hens Mahesh suffered a loss equal to the selling price of 6 hens. His loss per cent is

a) 9%

b) 3%

c) 4$1/2$%

d) 4%

Answer: (d)

CP of 144 hens - SP of 144 hens = Loss = SP of 6 hens

SP of 150 hens = CP of 144 hens

Let CP of each hen = Rs.1

CP of 150 hens = Rs.150

SP of 150 hens = Rs.144

Loss% = $6/150$ × 100 = 4%

Using Rule 9, On selling 'x' articles the profit or loss is equal to Selling of 'y' articles, then Profit% ${y × 100}/{x + y}$Loss% = ${y × 100}/{x + y}$

Here, x = 144, y = 6

∴ Loss% = ${y × 100}/{x + y}$

= $600/{144 + 6}$

= $600/150$ = 4%

Question : 3

A vendor loses the selling price of 4 oranges on selling 36 oranges. His loss per cent is

a) 10%

b) 9%

c) 11$1/2$%

d) 12$1/2$%

Answer: (a)

S.P. of 36 oranges

= C.P. of 36 oranges - S.P. of 4 oranges

S.P. of 40 oranges = C.P. of 36 oranges

Loss per cent = $4/40 × 100 = 10%$

Using Rule 9,

Here, x = 36, y = 4

Here, loss % = ${y × 100}/{x + y}$

= ${4 × 100}/{36 + 4}$ = 10%

Question : 4

A clock was sold for 144. If the percentage of profit was numerically equal to the cost price, the cost of the clock was

a) 90

b) 80

c) 100

d) 72

Answer: (b)

Let the cost price be x.

(100 + x)% of x = 144

(100 + x)x = 14400

$x^2 + 100x - 14400$ = 0

$x^2 + 180x - 80x - 14400$ = 0

x(x + 180) - 80 (x + 180) = 0

(x + 180) (x - 80) = 0

x = Rs.80 [x ≠180]

Question : 5

An article is sold at a certain price. If it is sold at half of the previous selling price, then there is a loss of 25$1/2$ % . The profit after selling the article at the previous selling price is:

a) 12$3/4$%

b) 49%

c) 24$1/2$%

d) 51%

Answer: (b)

Let the C.P. of article be Rs.100 and its S.P. be Rs.x.

According to the question.

When S.P. = Rs.$x/2$

Loss per cent = ${100 - x/2}/100 × 100$

$100 - x/2 = 51/2$

$x/2 = 100 - 51/2 = {200 - 51}/2$

x = Rs.149

Required profit percent = 49%

Question : 6

On selling 17 balls at 720, there is a loss equal to the cost price of 5 balls. The cost price (in ) of a ball is

a) 55

b) 50

c) 60

d) 45

Answer: (c)

Let C.P. of a ball = x

S.P. of 17 balls = Rs.720

17x - 720 = 5x

12x = 720 ⇒ x = Rs.60

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GET profit & loss PRACTICE TEST EXERCISES

Model 1 Basic Concepts of C.P and S.P

model 2 gain lost percentage

model 3 gain/loss % with C.P/S.P

model 4 sold & brought

model 5 marked price

model 6 sold in circular path

model 7 sold at loss

model 8 two article sold in different rates

model 9 selling an article & interchanging its values

model 10 reduced/increased price of an article

model 11 ratio & partnership
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