Model 1 Basic Concepts of C.P and S.P Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (b)

C.P. of article = Rs.x (let)

S.P. of article = Rs.${4x}/3$

Gain = ${4x}/3 - x = {4x - 3x}/3$ = Rs.$x/3$

Gain per cent = ${x/3}/x × 100$

= $100/3 = 33{1}/3%$

Answer: (d)

If the cost price be Rs.x, then

S.P. = $100/95x = Rs.20/19x$

Gain = ${20x}/19 - x = Rs.x/19$

Gain per cent = ${x/19}/x × 100 = 5.26%$

Using Rule 3,

Here C.P. = $95/100$ S.P.

C.P. = S.P.$(100/{100 + Profit%})$

$95/100$ S.P.

= S.P.$(100/{100 + Profit%})$

9500 + 95 profit% = 10000

Profit % = $500/95$ = 5.26%

Answer: (d)

CP of 75 litres of mixture of milk and water = Rs.630

SP of 75 litres of mixture of milk

and water = 9 × 75 = Rs.675

Gain = 675 - 630 = Rs.45

Gain per cent = $45/630 × 100 = 50/7 = 7{1}/7$%

Answer: (a)

Let the CP = Rs.100

Then, SP = Rs.120

Let the marked price = Rs.x.

Then, 90% of x = Rs.120

x = ${120 × 100}/90 = 400/3 = 133{1}/3$%

Hence, the marked price is

$33{1}/3$% above the cost price.

Answer: (d)

Using Rule 1,

S.P. = Rs.100; C.P. = Rs.80

Gain = Rs.20

∴ Gain per cent = $20/80 ×100$ = 25%

Answer: (c)

C.P. of 1 bucket = x

C.P. of 1 mug = y

8x + 5y = 92 .....(i)

5x + 8y = 77 .....(ii)

By using equation (i) × 5 - equation (ii) × 8,

40x + 25y - 40x - 64y

= 460 - 616

- 39y = - 156 ⇒ y = 4

From equation (i),

8x + 20 = 92

8x = 92 - 20 = 72 ⇒ x = 9

C.P. of 2 mugs and 3 buckets

= 2 × 4 + 3 × 9

= 8 + 27 = Rs.35