Model 1 Basic Concepts of C.P and S.P Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 11 EXERCISES
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New 249+ Profit and Loss Questions and Answers for TNPSC »
The following question based on profit & loss topic of quantitative aptitude
(a) 33$1/3$%
(b) 133$1/3$%
(c) 25%
(d) 30%
The correct answers to the above question in:
Answer: (a)
Let the CP = Rs.100
Then, SP = Rs.120
Let the marked price = Rs.x.
Then, 90% of x = Rs.120
x = ${120 × 100}/90 = 400/3 = 133{1}/3$%
Hence, the marked price is
$33{1}/3$% above the cost price.
Discuss Form
Read more basic cp and sp Based Quantitative Aptitude Questions and Answers
Question : 1
By selling 33 metres of cloth, a person gains the cost of 11 metres. Find his gain%.
a) 33%
b) 33$1/2$%
c) 33$1/3$%
d) 34$1/3$%
Answer »Answer: (c)
Gain per cent
= $11/33 × 100 = 100/3 = 33{1}/3$%
Question : 2
If selling price of an article is 1$1/3$ of cost price, find gain %.
a) 1.33%
b) 33$1/3$%
c) 25%
d) 66$2/3$%
Answer »Answer: (b)
C.P. of article = Rs.x (let)
S.P. of article = Rs.${4x}/3$
Gain = ${4x}/3 - x = {4x - 3x}/3$ = Rs.$x/3$
Gain per cent = ${x/3}/x × 100$
= $100/3 = 33{1}/3%$
Question : 3
If the cost price is 95% of the selling price, what is the profit per cent ?
a) 5%
b) 4.75%
c) 4%
d) 5.26%
Answer »Answer: (d)
If the cost price be Rs.x, then
S.P. = $100/95x = Rs.20/19x$
Gain = ${20x}/19 - x = Rs.x/19$
Gain per cent = ${x/19}/x × 100 = 5.26%$
Using Rule 3,
Here C.P. = $95/100$ S.P.
C.P. = S.P.$(100/{100 + Profit%})$
$95/100$ S.P.
= S.P.$(100/{100 + Profit%})$
9500 + 95 profit% = 10000
Profit % = $500/95$ = 5.26%
Question : 4
If the cost price of an article is 80% of its selling price, the profit per cent is :
a) 24%
b) 22$1/2$%
c) 20 %
d) 25%
Answer »Answer: (d)
Using Rule 1,
S.P. = Rs.100; C.P. = Rs.80
Gain = Rs.20
∴ Gain per cent = $20/80 ×100$ = 25%
Question : 5
The total cost of 8 buckets and 5 mugs is Rs.92 and the total cost of 5 buckets and 8 mugs is Rs.77. Find the cost of 2 mugs and 3 buckets.
a) Rs.30
b) Rs.70
c) Rs.35
d) Rs.38
Answer »Answer: (c)
C.P. of 1 bucket = x
C.P. of 1 mug = y
8x + 5y = 92 .....(i)
5x + 8y = 77 .....(ii)
By using equation (i) × 5 - equation (ii) × 8,
40x + 25y - 40x - 64y
= 460 - 616
- 39y = - 156 ⇒ y = 4
From equation (i),
8x + 20 = 92
8x = 92 - 20 = 72 ⇒ x = 9
C.P. of 2 mugs and 3 buckets
= 2 × 4 + 3 × 9
= 8 + 27 = Rs.35
Question : 6
If there is a profit of 20% on the cost price, the per centage of profit on the sale price is
a) 15$1/3$%
b) 12 %
c) 16$2/3$%
d) 16 %
Answer »Answer: (c)
Cost price = Rs.x
S.P. = ${120x}/100$ = Rs.${6x}/5$
Gain = Rs.$x/5$
Required gain per cent = ${x/5}/{{6x}/5} × 100$
= $100/6 = 50/3 = 16{2}/3$%
GET profit & loss PRACTICE TEST EXERCISES
Model 1 Basic Concepts of C.P and S.P
model 2 gain lost percentage
model 3 gain/loss % with C.P/S.P
model 4 sold & brought
model 5 marked price
model 6 sold in circular path
model 7 sold at loss
model 8 two article sold in different rates
model 9 selling an article & interchanging its values
model 10 reduced/increased price of an article
model 11 ratio & partnership
profit & loss Shortcuts and Techniques with Examples
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Model 1 Basic Concepts of C.P and S.P
Defination & Shortcuts … -
model 2 gain lost percentage
Defination & Shortcuts … -
model 3 gain/loss % with C.P/S.P
Defination & Shortcuts … -
model 4 sold & brought
Defination & Shortcuts … -
model 5 marked price
Defination & Shortcuts … -
model 6 sold in circular path
Defination & Shortcuts … -
model 7 sold at loss
Defination & Shortcuts … -
model 8 two article sold in different rates
Defination & Shortcuts … -
model 9 selling an article & interchanging its values
Defination & Shortcuts … -
model 10 reduced/increased price of an article
Defination & Shortcuts … -
model 11 ratio & partnership
Defination & Shortcuts …
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