Model 1 Basic Concepts of C.P and S.P Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on profit & loss topic of quantitative aptitude

Questions : The total cost of 8 buckets and 5 mugs is Rs.92 and the total cost of 5 buckets and 8 mugs is Rs.77. Find the cost of 2 mugs and 3 buckets.

(a) Rs.30

(b) Rs.70

(c) Rs.35

(d) Rs.38

The correct answers to the above question in:

Answer: (c)

C.P. of 1 bucket = x

C.P. of 1 mug = y

8x + 5y = 92 .....(i)

5x + 8y = 77 .....(ii)

By using equation (i) × 5 - equation (ii) × 8,

40x + 25y - 40x - 64y

= 460 - 616

- 39y = - 156 ⇒ y = 4

From equation (i),

8x + 20 = 92

8x = 92 - 20 = 72 ⇒ x = 9

C.P. of 2 mugs and 3 buckets

= 2 × 4 + 3 × 9

= 8 + 27 = Rs.35

Practice profit & loss (Model 1 Basic Concepts of C.P and S.P) Online Quiz

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Read more basic cp and sp Based Quantitative Aptitude Questions and Answers

Question : 1

If the cost price of an article is 80% of its selling price, the profit per cent is :

a) 24%

b) 22$1/2$%

c) 20 %

d) 25%

Answer: (d)

Using Rule 1,

S.P. = Rs.100; C.P. = Rs.80

Gain = Rs.20

∴ Gain per cent = $20/80 ×100$ = 25%

Question : 2

By what per cent must the cost price be raised in fixing the sale price in order that there may be a profit of 20% after allowing a commission of 10% ?

a) 33$1/3$%

b) 133$1/3$%

c) 25%

d) 30%

Answer: (a)

Let the CP = Rs.100

Then, SP = Rs.120

Let the marked price = Rs.x.

Then, 90% of x = Rs.120

x = ${120 × 100}/90 = 400/3 = 133{1}/3$%

Hence, the marked price is

$33{1}/3$% above the cost price.

Question : 3

By selling 33 metres of cloth, a person gains the cost of 11 metres. Find his gain%.

a) 33%

b) 33$1/2$%

c) 33$1/3$%

d) 34$1/3$%

Answer: (c)

Gain per cent

= $11/33 × 100 = 100/3 = 33{1}/3$%

Question : 4

If there is a profit of 20% on the cost price, the per centage of profit on the sale price is

a) 15$1/3$%

b) 12 %

c) 16$2/3$%

d) 16 %

Answer: (c)

Cost price = Rs.x

S.P. = ${120x}/100$ = Rs.${6x}/5$

Gain = Rs.$x/5$

Required gain per cent = ${x/5}/{{6x}/5} × 100$

= $100/6 = 50/3 = 16{2}/3$%

Question : 5

By selling a car for Rs.64,000, Mr. Rao lost 20%. Then the cost price of the car is :

a) Rs.80,000

b) Rs.76,800

c) Rs.72,000

d) Rs.84,000

Answer: (a)

Using Rule 3,

Cost price = ${64000 × 100}/80$ = Rs.80000

Question : 6

By selling an article for Rs.960 a man incurs a loss of 4%; what was the cost price ?

a) Rs.498.4

b) Rs.784

c) Rs.1,000

d) Rs.300

Answer: (c)

Using Rule 3,
If an object is sold on r% Profit.

then,S.P. = C.P$[{100 + \text"Profit%"}/100]$
or
C.P. = S.P$[100/{100 + \text"Profit%"}]$

Similarly, If an object is sold on r% loss, then

S.P. = C.P.$[{100 - \text"Loss%"}/100]$
or
C.P. = S.P$[100/{100 - \text"Loss%"}]$

C.P. of article = $100/{100 - \text"loss per cent"}$ × S.P.

= $100/96 × 960$ = Rs.1000

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