# Model 10 Percentage With Allegations & Mixture Section-Wise Topic Notes With Detailed Explanation And Example Questions

#### Top 10,000+ Aptitude Memory Based Exercises

The following question based on Percentage topic of Quantitative Aptitude

Questions : How much water must be added to 100 ml of 80 per cent solution of boric acid to reduce it to a 50 per cent solution ?

(a) 60 ml

(b) 30 ml

(c) 40 ml

(d) 50 ml

The correct answers to the above question in:

Let x ml of water be added.

\${20 + x}/{100 + x} × 100\$ = 50

40 + 2x = 100 + x ⇒ x = 60 ml

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#### Read more allegations mixture based Based Quantitative Aptitude Questions and Answers

Question : 1

In 50 gm alloy of gold and silver, the gold is 80% by weight. How much gold should be mixed to this alloy so that the weight of gold would become 95% ?

a) 10 gm

b) 200 gm

c) 150 gm

d) 50 gm

Initial quantity of gold

= \${50 × 80}/100\$ = 40 gm

Let 'x ' gm be mixed.

\$(40 + x) = (50 + x) × 95/100\$

\$40 + x =(50 + x) × 19/20\$

800 + 20x = 950 + 19x

x = 150 gm

Question : 2

40 litres of a mixture of milk and water contains 10% of water, the water to be added, to make the water content 20% in the new mixture is :

a) 5 litres

b) 6 litres

c) 6.5 litres

d) 5.5 litres

Water content in 40 litres of mixture = \$40 × 10/100\$ = 4 litres

Milk content = 40 – 4 = 36 litres

Let x litres of water is mixed.

Then, \${4 + x}/{40 + x} = 20/100\$

\${4 + x}/{40 + x} = 1/5\$

20 + 5x = 40 + x

4x = 20 ⇒ x = 5 litres

Question : 3

The ratio in which two sugar solutions of the concentrations 15% and 40% are to be mixed to get a solution of concentration 30% is

a) 9 : 8

b) 2 : 3

c) 3 : 2

d) 8 : 9

Required ratio = 10 : 15 = 2 : 3

Question : 4

300 grams of sugar solution has 40% of sugar in it. How much sugar should be added to make it 50% in the solution?

a) 80 gram

b) 40 gram

c) 10 gram

d) 60 gram

In 300 gm of solution,

Sugar = \${300 × 40}/100 = 120gm.\$

Let x gm of sugar be mixed.

According to the question,

\${120 + x}/{300 + x} =1/2\$

240 + 2x = 300 + x

2x – x = 300 – 240 ⇒ x = 60 gm.

Question : 5

75 gm of sugar solution has 30% sugar in it. Then the quantity of sugar that should be added to the solution to make the quantity of the sugar 70% in the solution, is

a) 130 gm

b) 125 gm

c) 100 gm

d) 120 gm

Sugar in original solution

= \${75 × 30}/100\$ = 22.5gm

Let x gm of sugar be mixed.

\${22.5 + x}/{75 + x} × 100 = 70\$

2250 + 100x = 75 × 70 + 70x

2250 + 100x = 5250 + 70x

30x = 5250 – 2250 = 3000

x = \$3000/30\$ = 100 gm

Question : 6

In what ratio must 25% of alcohol be mixed with 50% of alcohol to get a mixture of 40% strength alcohol ?

a) 3 : 2

b) 1 : 2

c) 2 : 1

d) 2 : 3

Required ratio = \$1/10 : 3/20 = 2 : 3\$

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