Model 10 Percentage With Allegations & Mixture SectionWise Topic Notes With Detailed Explanation And Example Questions
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The following question based on Percentage topic of Quantitative Aptitude
(a) 130 gm
(b) 125 gm
(c) 100 gm
(d) 120 gm
The correct answers to the above question in:
Answer: (c)
Sugar in original solution
= ${75 × 30}/100$ = 22.5gm
Let x gm of sugar be mixed.
${22.5 + x}/{75 + x} × 100 = 70$
2250 + 100x = 75 × 70 + 70x
2250 + 100x = 5250 + 70x
30x = 5250 – 2250 = 3000
x = $3000/30$ = 100 gm
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Read more allegations mixture based Based Quantitative Aptitude Questions and Answers
Question : 1
300 grams of sugar solution has 40% of sugar in it. How much sugar should be added to make it 50% in the solution?
a) 80 gram
b) 40 gram
c) 10 gram
d) 60 gram
Answer »Answer: (d)
In 300 gm of solution,
Sugar = ${300 × 40}/100 = 120gm.$
Let x gm of sugar be mixed.
According to the question,
${120 + x}/{300 + x} =1/2$
240 + 2x = 300 + x
2x – x = 300 – 240 ⇒ x = 60 gm.
Question : 2
How much water must be added to 100 ml of 80 per cent solution of boric acid to reduce it to a 50 per cent solution ?
a) 60 ml
b) 30 ml
c) 40 ml
d) 50 ml
Answer »Answer: (a)
Let x ml of water be added.
${20 + x}/{100 + x} × 100$ = 50
40 + 2x = 100 + x ⇒ x = 60 ml
Question : 3
In 50 gm alloy of gold and silver, the gold is 80% by weight. How much gold should be mixed to this alloy so that the weight of gold would become 95% ?
a) 10 gm
b) 200 gm
c) 150 gm
d) 50 gm
Answer »Answer: (c)
Initial quantity of gold
= ${50 × 80}/100$ = 40 gm
Let 'x ' gm be mixed.
$(40 + x) = (50 + x) × 95/100$
$40 + x =(50 + x) × 19/20$
800 + 20x = 950 + 19x
x = 150 gm
Question : 4
In what ratio must 25% of alcohol be mixed with 50% of alcohol to get a mixture of 40% strength alcohol ?
a) 3 : 2
b) 1 : 2
c) 2 : 1
d) 2 : 3
Answer »Answer: (d)
Required ratio = $1/10 : 3/20 = 2 : 3$
Question : 5
200 litres of a mixture contains 15% water and the rest is milk. The amount of milk that must be added so that the resulting mixture contains 87.5% milk is
a) 45 litres
b) 30 litres
c) 35 litres
d) 40 litres
Answer »Answer: (d)
In 200 litres of mixture,
Quantity of milk = 85 100 ´ 200 = 170 litres
Quantity of water = 30 litres
Let the quantity of additional milk added be x litres.
According to the question,
${170 + x}/{200 + x} × 100 = 87.5$
(170 +x) × 100 = 17500 + 87.5x
100x – 87.5x = 17500 – 17000
12.5x = 500
x = $500/12.5$ = 40 litres
GET PERCENTAGE PRACTICE TEST EXERCISES
Model 1 Simple Percentage Questions
Model 2 Net Increase Or Decrease In %
Model 3 Reducing & Exceeding Prices
Model 4 X & Y Comparison
Model 5 Income & Expenditure
Model 6 Consumption & Remaining
Model 7 Marks Scored In Examinations
Model 8 Population Based
Model 9 Voters & Election
Model 10 Percentage With Allegations & Mixture
Model 11 Percentage With Ratios
Percentage Shortcuts and Techniques with Examples

model 1 simple percentage questions
Defination & Shortcuts … 
model 2 net increase or decrease in %
Defination & Shortcuts … 
model 3 reducing & exceeding prices
Defination & Shortcuts … 
model 4 x & y comparison
Defination & Shortcuts … 
model 5 income & expenditure
Defination & Shortcuts … 
model 6 consumption & remaining
Defination & Shortcuts … 
model 7 marks scored in examinations
Defination & Shortcuts … 
Model 8 population based
Defination & Shortcuts … 
model 9 voters & election
Defination & Shortcuts … 
model 10 percentage with allegations & mixture
Defination & Shortcuts … 
model 11 percentage with ratios
Defination & Shortcuts …
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