model 10 percentage with allegations & mixture Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 11 EXERCISES

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The following question based on percentage topic of quantitative aptitude

Questions : In what ratio must 25% of alcohol be mixed with 50% of alcohol to get a mixture of 40% strength alcohol ?

(a) 3 : 2

(b) 1 : 2

(c) 2 : 1

(d) 2 : 3

The correct answers to the above question in:

Answer: (d)

Required ratio = $1/10 : 3/20 = 2 : 3$

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Read more allegations mixture based Based Quantitative Aptitude Questions and Answers

Question : 1

75 gm of sugar solution has 30% sugar in it. Then the quantity of sugar that should be added to the solution to make the quantity of the sugar 70% in the solution, is

a) 130 gm

b) 125 gm

c) 100 gm

d) 120 gm

Answer: (c)

Sugar in original solution

= ${75 × 30}/100$ = 22.5gm

Let x gm of sugar be mixed.

${22.5 + x}/{75 + x} × 100 = 70$

2250 + 100x = 75 × 70 + 70x

2250 + 100x = 5250 + 70x

30x = 5250 – 2250 = 3000

x = $3000/30$ = 100 gm

Question : 2

300 grams of sugar solution has 40% of sugar in it. How much sugar should be added to make it 50% in the solution?

a) 80 gram

b) 40 gram

c) 10 gram

d) 60 gram

Answer: (d)

In 300 gm of solution,

Sugar = ${300 × 40}/100 = 120gm.$

Let x gm of sugar be mixed.

According to the question,

${120 + x}/{300 + x} =1/2$

240 + 2x = 300 + x

2x – x = 300 – 240 ⇒ x = 60 gm.

Question : 3

How much water must be added to 100 ml of 80 per cent solution of boric acid to reduce it to a 50 per cent solution ?

a) 60 ml

b) 30 ml

c) 40 ml

d) 50 ml

Answer: (a)

Let x ml of water be added.

${20 + x}/{100 + x} × 100$ = 50

40 + 2x = 100 + x ⇒ x = 60 ml

Question : 4

200 litres of a mixture contains 15% water and the rest is milk. The amount of milk that must be added so that the resulting mixture contains 87.5% milk is

a) 45 litres

b) 30 litres

c) 35 litres

d) 40 litres

Answer: (d)

In 200 litres of mixture,

Quantity of milk = 85 100 ´ 200 = 170 litres

Quantity of water = 30 litres

Let the quantity of additional milk added be x litres.

According to the question,

${170 + x}/{200 + x} × 100 = 87.5$

(170 +x) × 100 = 17500 + 87.5x

100x – 87.5x = 17500 – 17000

12.5x = 500

x = $500/12.5$ = 40 litres

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