# Model 10 Percentage With Allegations & Mixture Section-Wise Topic Notes With Detailed Explanation And Example Questions

#### Top 10,000+ Aptitude Memory Based Exercises

The following question based on Percentage topic of Quantitative Aptitude

Questions : 200 litres of a mixture contains 15% water and the rest is milk. The amount of milk that must be added so that the resulting mixture contains 87.5% milk is

(a) 45 litres

(b) 30 litres

(c) 35 litres

(d) 40 litres

The correct answers to the above question in:

In 200 litres of mixture,

Quantity of milk = 85 100 ´ 200 = 170 litres

Quantity of water = 30 litres

According to the question,

\${170 + x}/{200 + x} × 100 = 87.5\$

(170 +x) × 100 = 17500 + 87.5x

100x – 87.5x = 17500 – 17000

12.5x = 500

x = \$500/12.5\$ = 40 litres

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#### Read more allegations mixture based Based Quantitative Aptitude Questions and Answers

Question : 1

In what ratio must 25% of alcohol be mixed with 50% of alcohol to get a mixture of 40% strength alcohol ?

a) 3 : 2

b) 1 : 2

c) 2 : 1

d) 2 : 3

Required ratio = \$1/10 : 3/20 = 2 : 3\$

Question : 2

75 gm of sugar solution has 30% sugar in it. Then the quantity of sugar that should be added to the solution to make the quantity of the sugar 70% in the solution, is

a) 130 gm

b) 125 gm

c) 100 gm

d) 120 gm

Sugar in original solution

= \${75 × 30}/100\$ = 22.5gm

Let x gm of sugar be mixed.

\${22.5 + x}/{75 + x} × 100 = 70\$

2250 + 100x = 75 × 70 + 70x

2250 + 100x = 5250 + 70x

30x = 5250 – 2250 = 3000

x = \$3000/30\$ = 100 gm

Question : 3

300 grams of sugar solution has 40% of sugar in it. How much sugar should be added to make it 50% in the solution?

a) 80 gram

b) 40 gram

c) 10 gram

d) 60 gram

In 300 gm of solution,

Sugar = \${300 × 40}/100 = 120gm.\$

Let x gm of sugar be mixed.

According to the question,

\${120 + x}/{300 + x} =1/2\$

240 + 2x = 300 + x

2x – x = 300 – 240 ⇒ x = 60 gm.

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