model 8 two article sold in different rates Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on profit & loss topic of quantitative aptitude

Questions : A man bought a horse anda carriage for Rs.40,000. He sold the horse at a gain of 10 % and the carriage at a loss of 5%. He gained 1% on his whole transaction. The cost price of the horse was :

(a) Rs.20000

(b) Rs.18000

(c) Rs.16000

(d) Rs.15000

The correct answers to the above question in:

Answer: (c)

If the C.P. of horse be Rs.x, then

C.P. of carriage = Rs.(40000 - x) Then,

${110 × x}/100 + {(40000 - x) × 95}/100 = {40000 × 101}/100$

110x + 3800000 - 95x = 4040000

15x = 4040000 - 3800000

15x = 240000 ⇒ x = $240000/15$ = Rs.16000

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Read more 2 articles sold in diff rates Based Quantitative Aptitude Questions and Answers

Question : 1

When the price of cloth was reduced by 25%, the quantity of cloth sold increased by 20%. What was the effect on gross receipt of the shop?

a) 10% decrease

b) 10% increase

c) 5% decrease

d) 5% increase

Answer: (a)

Using Rule 7,
If a% loss and b% profit occur then, total loss/profit is $(-a + b - {ab}/100)$%
(negative sign for loss and positive sign for profit)

Required per cent effect

= $(20 - 25 - {20 × 25}/100)%$

=( - 5 - 5)% = - 10% (10% decrease)

Negative sign shows decrease

Question : 2

A man bought two goats for Rs.1008. He sold one at a loss of 20% and other at a profit of 44%. If each goat was sold for the same price, the cost price of the goat which was sold at loss, was :

a) Rs.440

b) Rs.568

c) Rs.360

d) Rs.648

Answer: (d)

If x and y be the cost price of two goats, then,

80% of x = 144% of y

$x/y = 144/80 = 9/5$

i.e., x : y = 9 : 5

Sum of the ratios = 9 + 5 = 14

Cost of first goat = Rs.$(9/14 × 1008)$ = Rs.648

Question : 3

A shopkeeper sells an article at 15% gain. Had he sold it for Rs.18 more, he would have gained 18%. The cost price (in Rs.) of the article is

a) 350

b) 600

c) 318

d) 540

Answer: (b)

C.P. of article be Rs.x

(118 - 115)% of x = 18

${x × 3}/100 =18 ⇒ x = {18 ×100}/3$ = Rs.600

Using Rule 11,
A man sells his items at a profit/loss of x%.
If he had sold it for Rs. R more,
he would have gained/lost y%.
Then. C.P. of items = $R/{(y ± x)}$ × 100
'+' = When one is profit and other is loss.
' - ' = When both are either profit or loss.

Here, x = 15%, R= 18, y = 18%

C.P. = ${R × 100}/{y - x}$

= ${18 ×100}/{18 -15}$ = Rs.600

Question : 4

A cloth merchant sold half of his cloth at 20% profit, half of the remaining cloth at 20% loss and the rest was sold at his cost price. In the total transaction, his gain or loss will be

a) 10% profit

b) 5% loss

c) Neither loss nor gain

d) 5% profit

Answer: (d)

Total CP = Rs.100

Total SP = Rs.$({50 × 120}/100 + {25 × 80}/100 + 25)$

= Rs.(60 + 20 + 25) = Rs.105

Gain% = 5% $[{105 - 100}/100 × 100]$

Question : 5

A dealer sold two types of goods for Rs.10,000 each. On one of them, he lost 20% and on the other he gained 20%. His gain or loss per cent in the entire transaction was

a) 4% loss

b) 4% gain

c) 2% gain

d) 2% loss

Answer: (a)

Using Rule 10,

Here, S.P. is same. Hence there is always a loss.

Loss per cent = ${20 × 20}/100$ = 4%

Question : 6

A man buys a field of agricultural land for Rs.3,60,000. He sells onethird at a loss of 20% and twofifths at a gain of 25%. At what price must he sell the remaining field so as to make an overall profit of 10 % ?

a) Rs.1,25,000

b) Rs.1,20,000

c) Rs.1,15,000

d) Rs.1,00,000

Answer: (b)

SP of total agricultural field

= Rs.$(360000 × 110/100)$ = Rs.396000

SP of one - third of the field

= $1/3 × 360000 × 80/100$ = Rs.96000

SP of $2/5$th of the field

= $2/5 × 360000 × 125/100$ = Rs.180000

∴ SP of the remaining field

=Rs.(396000 - 96000 - 180000) = Rs.120000

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